Leetcode 0224: Basic Calculator

题目描述:

Given a string s representing an expression, implement a basic calculator to evaluate it.

Example 1:

Input: s = “1 + 1”
Output: 2

Example 2:

Input: s = " 2-1 + 2 "
Output: 3

Example 3:

Input: s = " 2-1 + 2 "
Output: 3

Constraints:

1 <= s.length <= 3 * 105
s consists of digits, ‘+’, ‘-’, ‘(’, ‘)’, and ’ '.
s represents a valid expression.

Time complexity: O(n)
Time complexity: O(n)

class Solution {
    
    
    public List<Integer> majorityElement(int[] nums) {
    
    
        List<Integer> res = new ArrayList<>();
        int c1 = 0;
        Integer n1 = nums[0];
        int c2 = 0;
        Integer n2 = nums[0];
        for (int n: nums) {
    
    
            if(n1 != null && n1 == n){
    
    
                c1++;
            }else if(n2 != null && n2 == n){
    
    
                c2++;
            }else if(c1 == 0){
    
    
                c1++;
                n1 = n;
            }else if(c2 == 0){
    
    
                c2++;
                n2 = n;
            }else{
    
    
                c1--;
                c2--;
            }
        }
        
        c1 = 0;
        c2 = 0;
        for (int n: nums) {
    
    
            if(n == n1){
    
    
                c1++;
            }else if(n == n2){
    
    
                c2++;
            }
        }
        int n = nums.length;
        if(c1 > n/3){
    
    
            res.add(n1);
        }
        if(c2 > n/3){
    
    
            res.add(n2);
        }
        return res;
    }
}

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转载自blog.csdn.net/weixin_43946031/article/details/113847320