算法:通过三个不同函数,将一个灰度值映射三个不同灰度值分别保存在三个不同的矩阵中,再把三个矩阵的值分别复制给一个新矩阵的三个通道中,这个新矩阵就是伪彩色图像矩阵,这样就由一张灰度图,得到一张伪彩色图像

标题

算法:通过三个不同函数,将一个灰度值映射三个不同灰度值分别保存在三个不同的矩阵中,再把三个矩阵的值分别复制给一个新矩阵的三个通道中,这个新矩阵就是伪彩色图像矩阵,这样就由一张灰度图,得到一张伪彩色图像。

 

 

int main()

{

         Mat grayImg = imread("D:\\2.jpg", 0);

         imshow("原图", grayImg);



         Mat R = grayImg.clone();

         Mat G = grayImg.clone();

         Mat B = grayImg.clone();



         int rows = grayImg.rows;

         int cols = grayImg.cols;

         for (int i = 0; i < rows; i++)

         {

                   for (int j = 0; j < cols; j++)

                   {

                            int current = grayImg.at<uchar>(i, j);

                            if (0 < current && current <= 64)

                            {

                                     R.at<uchar>(i, j) = 0;

                                     G.at<uchar>(i, j) = 4 * current;

                                     B.at<uchar>(i, j) = 255;

                            }

                            else if (64 < current && current <= 128)

                            {

                                     R.at<uchar>(i, j) = 0;

                                     G.at<uchar>(i, j) = 255;

                                     B.at<uchar>(i, j) = -4 * (current - 64) + 255;

                            }

                            else if (128 < current && current <= 192)

                            {

                                     R.at<uchar>(i, j) = 4 * (current - 128);

                                     G.at<uchar>(i, j) = 255;

                                     B.at<uchar>(i, j) = 0;

                            }

                            else

                            {

                                     R.at<uchar>(i, j) = 255;

                                     G.at<uchar>(i, j) = -4 * (current - 255);

                                     B.at<uchar>(i, j) = 0;

                            }

                   }

         }



         Mat channels[3];  //定义对象数组,分别存储三个通道

         Mat pseuMat;      //融合三个通道,存储在一个Mat里

         channels[0] = B;

         channels[1] = G;

         channels[2] = R;



         merge(channels, 3, pseuMat);

         imshow("效果图", pseuMat);



         waitKey(0);

         return 0;

}

 

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转载自blog.csdn.net/any1234567890/article/details/81195508
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