#include <stdio.h>
int is( int number );
void count_sum( int a, int b );
int main()
{
int a, b;
scanf("%d %d", &a, &b);
if (is(a)) printf("%d is counted.\n", a);
if (is(b)) printf("%d is counted.\n", b);
count_sum(a, b);
return 0;
}
int is( int number )
{
int count = 0, yu;
while(number >= 10)
{
yu = number % 10;
count += yu;
number = (int)(number/10);
}
count += number;
if(count == 5) return 1;
else return 0;
}
void count_sum( int a, int b )
{
int count = 0;
int sum = 0;
for(int i = a; i <= b; i++)
{
if(is(i))
{
count++;
sum = sum + i;
}
}
printf("count = %d, sum = %d",count,sum);
}
(PAT)一个函数判断给定正整数的各位数字之和是否等于5;另一个函数统计给定区间内有多少个满足上述要求的整数,并计算这些整数的和
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转载自blog.csdn.net/qq_52001969/article/details/111433395
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