编程实现: 两个int(32位)整数m和n的二进制表达中,有多少个位(bit)不同? 输入例子: 1999 2299 输出例子:7

程序代码:

#define _CRT_SECURE_NO_WARNINGS 1

#include<stdio.h>
#include <windows.h>

int main()
{
	int m = 0;
	int n = 0;
	int i = 0;
	int count = 0;
	printf("请输入两个整数:");
	scanf("%d %d", &m, &n);
	for (i = 0; i < 32; i++)
	{
		if ((m & 1) != (n & 1))
		{
			count++;
		}
		m = m >> 1;
		n = n >> 1;
	}
	printf("count=%d\n", count);
	system("pause");
	return 0;
}

运行界面:

猜你喜欢

转载自blog.csdn.net/xinwenhuayu/article/details/81512824