PAT (Basic Level) Practice (中文) B1034 有理数四则运算 (20 分)(C++)(分数四则运算)

版权声明:假装有个原创声明……虽然少许博文不属于完全原创,但也是自己辛辛苦苦总结的,转载请注明出处,感谢! https://blog.csdn.net/m0_37454852/article/details/86593071

1034 有理数四则运算 (20 分)
本题要求编写程序,计算 2 个有理数的和、差、积、商。

输入格式:

输入在一行中按照 a1/b1 a2/b2 的格式给出两个分数形式的有理数,其中分子和分母全是整型范围内的整数,负号只可能出现在分子前,分母不为 0。

输出格式:

分别在 4 行中按照 有理数1 运算符 有理数2 = 结果 的格式顺序输出 2 个有理数的和、差、积、商。注意输出的每个有理数必须是该有理数的最简形式 k a/b,其中 k 是整数部分,a/b 是最简分数部分;若为负数,则须加括号;若除法分母为 0,则输出 Inf。题目保证正确的输出中没有超过整型范围的整数。

输入样例 1:

2/3 -4/2
输出样例 1:

2/3 + (-2) = (-1 1/3)
2/3 - (-2) = 2 2/3
2/3 * (-2) = (-1 1/3)
2/3 / (-2) = (-1/3)
输入样例 2:

5/3 0/6
输出样例 2:

1 2/3 + 0 = 1 2/3
1 2/3 - 0 = 1 2/3
1 2/3 * 0 = 0
1 2/3 / 0 = Inf

using namespace std;
#include<algorithm>
#include<iostream>
#include<cstdio>

typedef struct Fraction//分数结构体
{
    long long int up, down;//分子分母
}Fraction;
Fraction A, B;

long long int gcd(long long int a, long long int b)//求最大公约数
{
    if(!b) return a;
    return gcd(b, a%b);
}

Fraction reduction(Fraction X)//化简
{
    if(X.down < 0) X.up = -X.up, X.down = -X.down;
    if(!X.up) X.down = 1;
    else
    {
        long long int d = gcd(abs(X.up), abs(X.down));
        X.up /= d, X.down /= d;
    }
    return X;
}

void print_X(Fraction X)//打印某有理数
{
    X = reduction(X);
    if(!X.up) printf("0");
    else if(X.down == 1)
    {
        if(X.up < 0) printf("(%lld)", X.up);
        else printf("%lld", X.up);
    }
    else if(abs(X.up) > X.down)//假分数
    {
        if(X.up < 0)
        {
            printf("(%lld %lld/%lld)", X.up/X.down, abs(X.up%X.down), X.down);
        }
        else
        {
            printf("%lld %lld/%lld", X.up/X.down, X.up%X.down, X.down);
        }
    }
    else
    {
        if(X.up < 0) printf("(%lld/%lld)", X.up, X.down);
        else printf("%lld/%lld", X.up, X.down);
    }
}

void print(Fraction A, char ch, Fraction B)//打印有理数1 运算符 有理数2 = 
{
    print_X(A);
    printf(" %c ", ch);
    print_X(B);
    printf(" = ");
}

void print_result(Fraction R)//打印运算结果和回车
{
    print_X(R);
    printf("\n");
}

Fraction ADD(Fraction A, Fraction B)//加减乘除
{
    Fraction result;
    result.down = A.down*B.down;
    result.up = A.up*B.down + A.down*B.up;
    return result;
}
Fraction MINUS(Fraction A, Fraction B)
{
    Fraction result;
    result.down = A.down*B.down;
    result.up = A.up*B.down - A.down*B.up;
    return result;
}
Fraction MULTIPLY(Fraction A, Fraction B)
{
    Fraction result;
    result.down = A.down*B.down;
    result.up = A.up*B.up;
    return result;
}
Fraction DIVIDE(Fraction A, Fraction B)
{
    Fraction result;
    result.down = A.down*B.up;
    result.up = A.up*B.down;
    return result;
}


int main()
{
    scanf("%lld/%lld %lld/%lld", &A.up, &A.down, &B.up, &B.down);
    print(A, '+', B);
    print_result(ADD(A, B));
    print(A, '-', B);
    print_result(MINUS(A, B));
    print(A, '*', B);
    print_result(MULTIPLY(A, B));
    print(A, '/', B);
    if(!reduction(B).up) printf("Inf\n");//除数为0单独考虑
    else print_result(DIVIDE(A, B));
	return 0;
}

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