python zip()与zip(*ziped)以及list(zip(a,b))

#环境python3.7
>>> a = [0,0,1,2,4,5,6,7,5]
>>> b = [0,0,1,2,4,5,6,7,5]
>>> zip(a,b)
<zip object at 0x08C049E0> 
#我们会发现：zip(a,b)返回一个 object，试着解压缩吧

>>> c = zip(*zip(a,b))
>>> c
<zip object at 0x08C04A58>
#啊？解压缩也是个object，只是后面的地址不一样了！真的解压出来了吗？让我试试

>>> (g,h) = zip(a,b)
Traceback (most recent call last):
  File "<pyshell#19>", line 1, in <module>
    (g,h) = zip(a,b)
ValueError: too many values to unpack (expected 2)
#压缩之后是看不了的！那么解压缩后呢？

>>> (e,f) = c
>>> (e,f) 
((0, 0, 1, 2, 4, 5, 6, 7, 5), (0, 0, 1, 2, 4, 5, 6, 7, 5))
#可以确定就是解压缩

我们会发现不是像python2中那样了！！！

 参考地址：https://www.runoob.com/python/python-func-zip.html

a = [1,2,3,4,5,6,7]

b = [1,2,3,4,5,6,7]

print(zip(a,b))
for (i,j) in zip(a,b):
    print(i,j)
print(list(zip(a,b)))
for (i,j) in list(zip(a,b)):
    print(i,j)

#一直不明白，为什么明明zip(a,b)和list(zip(a,b)不一样，但是for循环结果一样的

#可能就类似于这个吧！
a = range(5)
print(a)

for i in a:
    print(i)

'''
输出：
<zip object at 0x031AE6E8>
1 1
2 2
3 3
4 4
5 5
6 6
7 7
[(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (7, 7)]
1 1
2 2
3 3
4 4
5 5
6 6
7 7
range(0, 5)
0
1
2
3
4
>>> 

'''