题目描述
找出所有员工当前(to_date='9999-01-01')具体的薪水salary情况，对于相同的薪水只显示一次,并按照逆序显示
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
输出描述
| salary |
|---|
| 94692 |
| 94409 |
| 88958 |
| 88070 |
| 74057 |
| 72527 |
| 59755 |
| 43311 |
| 25828 |
试题详解
首先用WHERE语句筛选、DISTINCT语句去重，之后通过ORDER BY和DESC降序排列。代码如下：
SELECT DISTINCT salary
FROM salaries
WHERE to_date = '9999-01-01'
ORDER BY salary DESC;