SELECT de.emp_no, de.dept_no, eb.btype, eb.recevied
FROM dept_emp AS de LEFT JOIN emp_bonus AS eb
ON de.emp_no = eb.emp_no;
数据库SQL实战(牛客网):获取所有员工的emp_no
猜你喜欢
转载自blog.csdn.net/weixin_43777983/article/details/105280336
今日推荐
周排行