应用场景:
连续点击会造成吐司两次
工具类如下:
public class ButtonUtil {
private static long lastClickTime = 0;
private static long DIFF = 1000;
private static int lastButtonId = -1;
/**
* 判断两次点击的间隔,如果小于1000,则认为是多次无效点击
*
* @return
*/
public static boolean isFastDoubleClick() {
return isFastDoubleClick(-1, DIFF);
}
/**
* 判断两次点击的间隔,如果小于1000,则认为是多次无效点击
*
* @return
*/
public static boolean isFastDoubleClick(int buttonId) {
return isFastDoubleClick(buttonId, DIFF);
}
/**
* 判断两次点击的间隔,如果小于diff,则认为是多次无效点击
*
* @param diff
* @return
*/
public static boolean isFastDoubleClick(int buttonId, long diff) {
long time = System.currentTimeMillis();
long timeD = time - lastClickTime;
if (lastButtonId == buttonId && lastClickTime > 0 && timeD < diff) {
Log.v("isFastDoubleClick", "短时间内按钮多次触发");
return true;
}
lastClickTime = time;
lastButtonId = buttonId;
return false;
}
}
使用:
hehe.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if(!ButtonUtil.isFastDoubleClick(R.id.hehe))
Toast.makeText(MainActivity.this, "sss", Toast.LENGTH_SHORT).show();
}
});