octave:29> clear
octave:30> syms x y z;
octave:31> a = x-3*y-2*z;
octave:32> b =2*x-4*y-3*z;
octave:33> c =-3*x+6*y+8*z;
octave:34> s =solve(a==6,b==8,c==-5)
s =
scalar structure containing the fields:
x =<classsym>
y =<classsym>
z =<classsym>
octave:35> x = s.x,y = s.y,z = s.z
x =(sym)1
y =(sym)-3
z =(sym)2
7
>> syms x;>> q =exp(x)-x.^2;>> s =solve(q==0)
s =-2*lambertw(0,-1/2)-2*lambertw(0,1/2)>>double(s)
ans =1.5880-1.5402i
-0.7035+0.0000i
8
>> syms x;>> q =tan(x).^2-sec(x).^2;>> s =simplify(q)
s =-1
9
>> syms x;>> q =taylor(tan(x),10)
q =
x + x^3/3+(2*x^5)/15+(17*x^7)/315+(62*x^9)/283
10 刚刚电脑突然卡死,MATLAB的数据也丢失了,就用网上的在线编辑器弄出了答案:
octave:37> clear
octave:38> syms x;
octave:39> q =4/(5-cos(x));
octave:40> s =taylor(q,'order',10,'expansionpoint',0)
s =(sym)8642241⋅x 113⋅x 5⋅x x
────── - ────── + ──── - ── +1258048230401928