Pytorch学习之旅(2)——梯度下降
简单线性回归问题求解
1、假设回归函数为 y = w * x + b,则损失值Loss=(w*x+b-y)^2。
2、定义损失值计算函数。
def compute_error_for_line_given_points(b, w, points):
totalError = 0
for i in range(0, len(points)):
x = points[i, 0]
y = points[i, 1]
totalError += (y - (w*x + b)) ** 2
return totalError / float(len(points))
3、定义单步梯度下降函数
def step_gradient(b_current, w_current, points, learningRate):
b_gradient = 0
w_gradient = 0
N = float(len(points))
for i in range(0, len(points)):
x = points[i, 0]
y = points[i, 1]
b_gradient -= (2/N) * (y - (w_current*x+b_current))
w_gradient -= (2/N) * (y - (w_current*x+b_current)) * x
new_b = b_current - (learningRate * b_gradient)
new_w = w_current - (learningRate * w_gradient)
return [new_b, new_w]
4、定义连续梯度下降函数
def gradient_descent_runner(points, starting_b, starting_w,
learning_rate, num_interations):
b = starting_b
w = starting_w
for i in range(num_interations):
b, w=step_gradient(b, w, np.array(points), learning_rate)
return [b, w]
5、主函数
def run():
points = np.genfromtxt("data.csv", delimiter=',')
learning_rate = 0.0001
initial_b = 0
initial_w = 0
num_interation = 1000
print("Starting gradient desent at b = {0} , w = {1}, error={2}"
.format(initial_b, initial_w, compute_error_for_line_given_points(initial_b, initial_w, points)))
print("Runing...")
[b, w] = gradient_descent_runner(points, initial_b, initial_w, learning_rate, num_interation)
print("Ending gradient desent at b = {0} , w = {1}, error={2}"
.format(b, w, compute_error_for_line_given_points(initial_b, initial_w, points)))
if __name__ == '__main__':
run()