C#计算两个经纬度的距离

原文: C#计算两个经纬度的距离

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//地球半径，单位米         private const double EARTH_RADIUS = 6378137;         /// <summary>         /// 计算两点位置的距离，返回两点的距离，单位 米         /// 该公式为GOOGLE提供，误差小于0.2米         /// </summary>         /// <param name="lat1">第一点纬度</param>         /// <param name="lng1">第一点经度</param>         /// <param name="lat2">第二点纬度</param>         /// <param name="lng2">第二点经度</param>         /// <returns></returns>         public static double GetDistance( double lat1, double lng1, double lat2, double lng2)         {             double radLat1 = Rad(lat1);             double radLng1 = Rad(lng1);             double radLat2 = Rad(lat2);             double radLng2 = Rad(lng2);             double a = radLat1 - radLat2;             double b = radLng1 - radLng2;             double result = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a / 2), 2) + Math.Cos(radLat1) * Math.Cos(radLat2) * Math.Pow(Math.Sin(b / 2), 2))) * EARTH_RADIUS;             return result;         }           /// <summary>         /// 经纬度转化成弧度         /// </summary>         /// <param name="d"></param>         /// <returns></returns>         private static double Rad( double d)         {             return ( double )d * Math.PI / 180d;         }