输入a和n,求a+aa+aaa+a....a(n个a之和)
//求a的连续和,
#include <stdio.h>
int main()
{
int a,n,i,j;
int temp,sum;
sum=0;
scanf("%d%d",&a,&n);
temp=0;
for(j=1;j<=n;j++){
temp=10*temp+a;
sum=sum+temp;
}
printf("%d",sum);
return 0;
}
//求a的连续和,
#include <stdio.h>
int main()
{
int a,n,i,j;
int temp,sum;
sum=0;
scanf("%d%d",&a,&n);
temp=0;
for(j=1;j<=n;j++){
temp=10*temp+a;
sum=sum+temp;
}
printf("%d",sum);
return 0;
}