二叉树---判断是不是子树

二叉树A、B,判断B是不是A的子树

代码如下

public class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;

    public TreeNode(int val) {
        this.val = val;
    }
}
public class Solution {
    public boolean HasSubtree(TreeNode root1,TreeNode root2) {
        if(root2 == null || root1 == null) return false;
        return ifSub(root1,root2) || 
            HasSubtree(root1.left,root2) ||
            HasSubtree(root1.right,root2);
    }
    public boolean ifSub(TreeNode root1,TreeNode root2){
        if(root2 == null) return true;
        if(root1 == null) return false;//此时root2不为null,顺序不可变
        if(root1.val == root2.val)
            return ifSub(root1.left,root2.left) && ifSub(root1.right,root2.right);
        else return false;
    }
}

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转载自blog.csdn.net/machine_Heaven/article/details/103735337