Table of Contents
一、中文版
给你一个字符串 s 和一个 长度相同 的整数数组 indices 。
请你重新排列字符串 s ，其中第 i 个字符需要移动到 indices[i] 指示的位置。
返回重新排列后的字符串。
示例 1：
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输入：s = "codeleet", indices = [4,5,6,7,0,2,1,3]
输出："leetcode"
解释：如图所示，"codeleet" 重新排列后变为 "leetcode" 。
示例 2：
输入：s = "abc", indices = [0,1,2]
输出："abc"
解释：重新排列后，每个字符都还留在原来的位置上。
示例 3：
输入：s = "aiohn", indices = [3,1,4,2,0]
输出："nihao"
示例 4：
输入：s = "aaiougrt", indices = [4,0,2,6,7,3,1,5]
输出："arigatou"
示例 5：
输入：s = "art", indices = [1,0,2]
输出："rat"
提示：
s.length == indices.length == n1 <= n <= 100s仅包含小写英文字母。0 <= indices[i] < nindices的所有的值都是唯一的（也就是说，indices是整数0到n - 1形成的一组排列）。
二、英文版
Given a string s and an integer array indices of the same length.
The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:
Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Example 3:
Input: s = "aiohn", indices = [3,1,4,2,0]
Output: "nihao"
Example 4:
Input: s = "aaiougrt", indices = [4,0,2,6,7,3,1,5]
Output: "arigatou"
Example 5:
Input: s = "art", indices = [1,0,2]
Output: "rat"
Constraints:
s.length == indices.length == n1 <= n <= 100scontains only lower-case English letters.0 <= indices[i] < n- All values of
indicesare unique (i.e.indicesis a permutation of the integers from0ton - 1).
三、My answer
class Solution:
def restoreString(self, s: str, indices: List[int]) -> str:
n = len(s)
result = ['0'] * n
for i in range(n):
result[indices[i]] = s[i]
result_str = ''.join(result)
return result_str四、解题报告
数据结构：数组
算法：遍历。需要清楚 indices[i] 是 result 的下标，s[i] 是 result[indices[i]] 的值。
题目特点：字符串 s 和数组 indices 长度相同