两数相加--伪头节点--C++

两数相加–伪头节点

在这里插入图片描述
创建伪头节点,数学加法运算。

struct ListNode {
    
    
      int val;
      ListNode *next;
      ListNode(int x) : val(x), next(NULL) {
    
    }
};
 
class Solution {
    
    
public:
    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
    
    
        
        if (l1 == NULL && l2 != NULL){
    
     return l2; }
        if (l1 != NULL && l2 == NULL){
    
     return l1; }
        if (l1 == NULL && l2 == NULL){
    
     return NULL; }
        
        ListNode *dummy_head = new ListNode(-1);
        ListNode *pre = dummy_head;
        
        while (l1 != NULL && l2 != NULL)
        {
    
    
            if (l1->val + l2->val < 10)
            {
    
    
                l1->val = l1->val + l2->val;
                    
            }
            else
            {
    
    
                l1->val = (l1->val + l2->val) - 10;
                if (l1->next != NULL && l2 -> next != NULL)
                {
    
    
                    l1->next->val = l1->next->val + 1;
                }
                else
                {
    
    
                    if (l1->next == NULL && l2 -> next != NULL)
                    {
    
    
                        l1->next = new ListNode(1);
                    }
                    else if (l1->next != NULL && l2 -> next == NULL)
                    {
    
    
                        l2->next = new ListNode(1);
                    }
                    else
                    {
    
    
                        l1->next = new ListNode(1);
                    }
                    
                }
                
            }
            
            pre->next = l1;
            pre = pre->next;
            l1 = l1->next;
            l2 = l2->next;
            
        }
        
        ListNode *p = dummy_head;
        dummy_head = dummy_head->next;
        delete p;
        
        if (l1 != NULL && l2 == NULL)
        {
    
    
            pre->next = l1;
            return dummy_head;
        }
        else if (l1 == NULL && l2 != NULL)
        {
    
    
            pre->next = l2;
            return dummy_head;
        }
        else
        {
    
    
            return dummy_head;
        }
        
    }
};

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转载自blog.csdn.net/qq_40550384/article/details/107026011