import os
import win32com.client as win32
import easygui as eg
def save_as_xlsx(fname):
excel = win32.DispatchEx('Excel.Application')
wb = excel.Workbooks.Open(fname)
wb.SaveAs(fname + "x", FileFormat=51) # FileFormat = 51 is for .xlsx extension
wb.Close() # FileFormat = 56 is for .xls extension
excel.Application.Quit()
def pick_package():
# 打开windows窗口，选择一个文件夹
return eg.diropenbox()
if __name__ == "__main__":
package = pick_package()
files = os.listdir(package)
for fname in files:
if fname.endswith(".xls"):
print(fname + "正在进行格式转换，请稍后~")
try:
currentfile = package + "\\" + fname
save_as_xlsx(currentfile)
print(currentfile + "格式转换完成，O(∩_∩)O哈哈~")
except:
print(currentfile + "格式转换异常，┭┮﹏┭┮")
else:
print("跳过非xls文件：" + fname)
input("输入任意键退出")
import os
import win32com.client as win32
import easygui as eg
def pick_package():
# 打开windows窗口，选择一个文件夹
return eg.diropenbox()
if __name__ == "__main__":
package = pick_package()
files = os.listdir(package)
import win32com.client as win32
fname = "C:\\Users\\laiwu\\PycharmProjects\\pythonProject1\\利润表"
excel = win32.gencache.EnsureDispatch('Excel.Application')
wb = excel.Workbooks.Open(fname)
wb.SaveAs(fname+"x", FileFormat = 51) #FileFormat = 51 is for .xlsx extension
wb.Close() #FileFormat = 56 is for .xls extension
excel.Application.Quit()
"""
用python批量获取某路径文件夹及子文件夹下的指定类型文件excel，并按指定路径进行存储
"""
import os
import shutil
file_excel = []
path = os.getcwd()
path_listdir = os.listdir(path)
for s in path_listdir:
path_excel = os.path.join(path, s) # 将文件名加入到当前文件路径后面
if os.path.isfile(path_excel): # 如果是文件
if os.path.splitext(path_excel)[1] == ".xlsx": # 如果文件是".pdb"后缀的
file_excel.append(path_excel)
# elif os.path.splitext(path_excel)[1] == ".xls":
# path_excel = path_excel + 'x'
# file_excel.append(path_excel)
# print(path_excel)
elif os.path.isdir(path_excel): # 如果是路径
continue
for i in range(len(file_excel)):
path_dir = os.path.split(file_excel[i])[0]
# print(path_dir)
path_file = os.path.split(file_excel[i])[1]
# print(path_file)
filename = path_dir + '/' + path_file
filename_bak = path + '/bak/' + path_file
shutil.copyfile(filename, filename_bak)