1dd a form to your page. Just a normal form, no special markup required: <form id="myForm" action="comment.php" method="post">
Name: <input type="text" name="name" />
Comment: <textarea name="comment"></textarea>
<input type="submit" value="Submit Comment" />
</form>
------------------------------------------------
2Include jQuery and the Form Plugin external script files and a short script to initialize the form when the DOM is ready: <html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
// wait for the DOM to be loaded
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$('#myForm').ajaxForm(function() {
alert("Thank you for your comment!");
});
});
</script>
</head>
...
----------------------------------------------------
举一个小例子
<script type="text/javascript">
</script>
<form id="personal" enctype="multipart/form-data" method="post">
<input type="hidden" id="photoName" name="photoName"/>
<input type="hidden" id="updateEditType" name="editType" value="update"></input>
</form>
<p><button onclick="submit()" 修改button></p>
-----------------------------
var personal = {
url: "",
beforeSubmit: showRequest,
success: showResponse
};
function showRequest(formData, jqForm, options) {
$('#msg').show();
return true;
}
function showResponse(responseText, statusText) {
$('#msg').html("操作完成!").hide();
alert("操作成功!");
$('#msg').hide();
//修改id="photo"的src属性
document.getElementById('photo').src = "";
$('#createEditType').val('update');
}
function submit(){
var photoName = document.getElementById('photoName').value;
if (photoName == "") {
alert("no,no,no,photo!");
return false;
}
$('#personal').ajaxSubmit(personalPortraitOptions);
}
jquery .form.js的使用方法
猜你喜欢
转载自1055592535.iteye.com/blog/1680400
今日推荐
周排行