pyhton rostopic发送、订阅demo

发送

#!/usr/bin/env python
#coding=utf-8
 
import rospy
from std_msgs.msg import String
 
def talker():
    pub = rospy.Publisher('chatter',String, queue_size=10)
    rospy.init_node('talker',anonymous=True)
    rate = rospy.Rate(10) # 10hz
    while not rospy.is_shutdown():
        hello_str = "超哥 好帅啊 %s" % rospy.get_time()
        rospy.loginfo(hello_str)
        pub.publish(hello_str)
        rate.sleep()
 
if __name__ == '__main__':
    try:
        talker()
    except rospy.ROSInterruptException:
        pass

订阅

#!/usr/bin/env python
#coding=utf-8
 
 
import rospy
from std_msgs.msg import String
 
def callback(data):
    rospy.loginfo(rospy.get_caller_id() + '我觉得 %s', data.data)
 
def listener():
 
    # In ROS, nodes are uniquely named. If two nodes with the same
    # name are launched, the previous one is kicked off. The
    # anonymous=True flag means that rospy will choose a unique
    # name for our 'listener' node so that multiple listeners can
    # run simultaneously.
#对上面注释翻译
    #在ROS中,节点是唯一命名的。 如果两个节点相同
    #名称被启动,前一个被启动。该
    #anonymous = True标志意味着rospy会选择一个独特的
    #我们的'侦听器'节点的名称,以便多个侦听器可以
    #同时运行。
     rospy.init_node('listener', anonymous=True)
 
    rospy.Subscriber('chatter', String, callback)
 
    # spin() simply keeps python from exiting until this node is stopped
    rospy.spin()
 
if __name__ == '__main__':
    listener()

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转载自blog.csdn.net/wuhchengfei616/article/details/107365761