tp5处理不可预知的内部异常api数据输出解决方案

在公用的common.php中创建show方法,客户端调用服务器端接口返回json数据

/*
 * 通用化API接口数据输出
 */
function show($status, $message, $data = [], $httpCode = 200){
    $data = [
        'status' => $status,
        'message' => $message,
        'data' => $data,
    ];
    return json($data, $httpCode);
}

在app/common/lib/exception/创建ApiException类

<?php


namespace app\common\lib\exception;


use think\Exception;

class ApiException extends Exception
{
    public $message = '';
    public $httpCode = 500;
    public $code = 0;

    public function __construct($message = "", $httpCode = 0, $code = 0)
    {
        $this->httpCode = $httpCode;
        $this->message = $message;
        $this->code = $code;
    }
}

在app/common/lib/exception/创建ApiHandleException类,让服务器端返回json格式的错误

<?php


namespace app\common\lib\exception;


use think\exception\Handle;

class ApiHandleException extends Handle
{
    /*
     * http状态码
     */
    public $httpCode = 500;
    public function render(\Exception $e)
    {
        if(config('app_debug') == true){
            return parent::render($e);
        }
        if($e instanceof ApiException){
            $this->httpCode = $e->httpCode;
        }
        return show(0, $e->getMessage(), [], $this->httpCode);
    }

}

修改config.php配置文件

 测试:

在控制器中输入如下代码:

public function save(){
        $data = input('post.');
        if($data['mt'] != 1){
            throw new ApiException('您提交的数据不合法', 400);
        }

        return show(1, 'OK', input('post.'), 201);
    }

postman中调用该方法

app_debug为true时返回下图时代码生效

app_debug为false时返回下图时代码生效 

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转载自blog.csdn.net/qq_43737121/article/details/105637554