leetcode-Database-183 |从不订购的客户

原题

思路

关联或者not in

代码

SELECT C.NAME AS Customers FROM Customers  C left join  Orders O on c.id=o.CustomerId where o.CustomerId is null

或者

这块我就觉得很不公平，为什么别人和我写的一样的，对方击败了百分之99…而我击败了百分之10，因为我没充会员？

SELECT C.NAME AS Customers FROM Customers  C where C.id not in (select CustomerId  from Orders )