using MyFuncType = string(*)(string, string);
string add0(string a, string b)
{
return a + b;
}
string add1(string a, string b)
{
return a + b + a;
}
int main()
{
MyFuncType fun = add0;
string strOut = fun("aa","bb");
}
C++把函数名作为变量传递
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转载自blog.csdn.net/Stone_Wang_MZ/article/details/108780710
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