python dataframe两列转为字典key和value，找出所有父节点

本意想找出产业链，但数据量太大，这方法不适用

dataframe两列转为字典key和value

import pandas as pd
import numpy as np
df = pd.DataFrame({"a":[1,1,1,2,2,2,2,3], "b": ["q","q","q","q","q","q","q","w"], "c":[0,0,0,0,0,0,0,0], "d": [1,1,1,1,1,1,1,1]})
print(df)
aa= df[["a", "b"]].set_index("a").to_dict()["b"]
print(aa)

结果：

   a  b  c  d
0  1  q  0  1
1  1  q  0  1
2  1  q  0  1
3  2  q  0  1
4  2  q  0  1
5  2  q  0  1
6  2  q  0  1
7  3  w  0  1
{1: 'q', 2: 'q', 3: 'w'}

Process finished with exit code 0

找出所有父节点

dict = {"南京企业爱普":"南京企业爱普22","南京企业爱普22":"南京企业爱普33","南京企业爱普":"河南胡辣汤","南京企业爱普1":"武汉热干面","北京烤鸭":"西安肉夹馍","深圳前海":"南京企业爱普"}
list = []
def get_father( word):
    if word not in dict.keys():
        return []
    else:
        c = dict[word]

        a = [dict[word]]

        b = get_father(c)

        return a + b
print(get_father("深圳前海"))

结果：

['南京企业爱普', '河南胡辣汤']

Process finished with exit code 0