DP

leetcode 132:
The key of dp problem is definition of state and inference of the relationship.
In this problem, we define dp[i] meaning the minimum cut from i to the end.
then the resolution is

 for (int i = len-1;i >= 0; --i){
            for (int j = i;j < len;++j){
                if ((s[i]==s[j] && j-i<2) || (s[i]==s[j]&&vis[i+1][j-1])){
                    vis[i][j] = true;
                    dp[i] = min(dp[i], dp[j+1]+1);
                }
            }
        }

you should also handle the problem of check whether the substring is palindrome or not. However, it’s not the concern in the article. So it’s just ignored.

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转载自blog.csdn.net/guojunxiu/article/details/79548303
DP
DP?