Problem 29

问题描述:

Consider all integer combinations of ab for 2 ≤a ≤ 5 and 2 ≤b ≤ 5:

2 2=4, 2 3=8, 2 4=16, 2 5=32
3 2=9, 3 3=27, 3 4=81, 3 5=243
4 2=16, 4 3=64, 4 4=256, 4 5=1024
5 2=25, 5 3=125, 5 4=625, 5 5=3125

If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:

4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125

How many distinct terms are in the sequence generated by ab for 2 ≤a ≤ 100 and 2 ≤b ≤ 100?

解决问题:

java里有set,每次计算出来,都将值放入其中,然后统计。

public static int count(){
		int total = 0;
		Set<Double> all = new HashSet<Double>();
		
		for(int i=DOWN; i<=UP; i++){
			for(int j=DOWN; j<=UP; j++){
				double value = Math.pow(i, j);
				all.add(value);
			}
		}
		
		return all.size();
	}

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转载自to-zoe-yang.iteye.com/blog/1151379
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