(二分法)力扣34.在排序数组中查找元素的第一个和最后一个位置

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class Solution {
    
    
    public int[] searchRange(int[] nums, int x) {
    
    
        if (nums == null || nums.length == 0) return new int[]{
    
    -1,-1};
        int l = 0,r = nums.length - 1;
        while (l < r) {
    
    
            int mid = l + r >> 1;
            if (nums[mid] >= x) r = mid;
            else l = mid + 1; 
        }
        int ans1 = l;
        if (nums[l] != x) return new int[]{
    
    -1,-1};
        else {
    
    
            l = 0;
            r = nums.length - 1;
            while (l < r) {
    
    
                int mid = l + r + 1 >> 1;
                if (nums[mid] <= x) l = mid;
                else r = mid - 1;
            }
        }
        return new int[]{
    
    ans1,l};  
    }
}

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转载自blog.csdn.net/Sherlook_Holmes/article/details/121209629