作业
1. 取得每个部门最高薪水的人员名称
第一步：取得每个部门最高薪水(按照部门编号分组，找出每一组最大值)
mysql> select deptno,max(sal) as maxsal from emp group by deptno;
+--------+---------+
| deptno | maxsal |
+--------+---------+
| 10 | 5000.00 |
| 20 | 3000.00 |
| 30 | 2850.00 |
+--------+---------+
第二步：将以上的查询结果当做一张临时表 t，
t 和 emp 表连接，条件：t.deptno = e.deptno and t.maxsal = e.sal
select
e.ename, t.*
from
emp e
join
(select deptno,max(sal) as maxsal from emp group by deptno) t
on
t.deptno = e.deptno and t.maxsal = e.sal;
+-------+--------+---------+
| ename | deptno | maxsal |
+-------+--------+---------+
| BLAKE | 30 | 2850.00 |
| SCOTT | 20 | 3000.00 |
| KING | 10 | 5000.00 |
| FORD | 20 | 3000.00 |
+-------+--------+---------+
2. 哪些人的薪水在部门的平均薪水之上
第一步：找出每个部门的平均薪水
select deptno,avg(sal) as avgsal from emp group by deptno;
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
| 20 | 2175.000000 |
| 30 | 1566.666667 |
+--------+-------------+
第二步：将以上查询结果当做 t 表，t 和 emp 表连接
条件：部门编号相同，并且 emp 的 sal 大于 t 表的 avgsal
select
t.*, e.ename, e.sal
from
emp e
join
(select deptno,avg(sal) as avgsal from emp group by deptno) t
on
e.deptno = t.deptno and e.sal > t.avgsal;
+--------+-------------+-------+---------+
| deptno | avgsal | ename | sal |
+--------+-------------+-------+---------+
| 30 | 1566.666667 | ALLEN | 1600.00 |
| 20 | 2175.000000 | JONES | 2975.00 |
| 30 | 1566.666667 | BLAKE | 2850.00 |
| 20 | 2175.000000 | SCOTT | 3000.00 |
| 10 | 2916.666667 | KING | 5000.00 |
| 20 | 2175.000000 | FORD | 3000.00 |
+--------+-------------+-------+---------+
3. 取得部门中（所有人的）平均的薪水等级
平均的薪水等级：先计算每一个薪水的等级，然后找出薪水等级的平均值。
平均薪水的等级：先计算平均薪水，然后找出每个平均薪水的等级值。
第一步：找出每个人的薪水等级
emp e 和 salgrade s 表连接。
连接条件：e.sal between s.losal and s.hisal
select
e.ename,e.sal,e.deptno,s.grade
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal;
+--------+---------+--------+-------+
| ename | sal | deptno | grade |
+--------+---------+--------+-------+
| CLARK | 2450.00 | 10 | 4 |
| KING | 5000.00 | 10 | 5 |
| MILLER | 1300.00 | 10 | 2 |
| SMITH | 800.00 | 20 | 1 |
| ADAMS | 1100.00 | 20 | 1 |
| SCOTT | 3000.00 | 20 | 4 |
| FORD | 3000.00 | 20 | 4 |
| JONES | 2975.00 | 20 | 4 |
| MARTIN | 1250.00 | 30 | 2 |
| TURNER | 1500.00 | 30 | 3 |
| BLAKE | 2850.00 | 30 | 4 |
| ALLEN | 1600.00 | 30 | 3 |
| JAMES | 950.00 | 30 | 1 |
| WARD | 1250.00 | 30 | 2 |
+--------+---------+--------+-------+
第二步：基于以上的结果继续按照 deptno 分组，求 grade 的平均值。
select
e.deptno,avg(s.grade)
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal
group by
e.deptno;
+--------+--------------+
| deptno | avg(s.grade) |
+--------+--------------+
| 10 | 3.6667 |
| 20 | 2.8000 |
| 30 | 2.5000 |
+--------+--------------+
4. 不准用组函数（Max ），取得最高薪水
第一种：sal 降序，limit 1
select ename,sal from emp order by sal desc limit 1;
+-------+---------+
| ename | sal |
+-------+---------+
| KING | 5000.00 |
+-------+---------+
第二种方案：表的自连接
select sal from emp where sal not in
(select distinct a.sal
from emp a
join emp b
on a.sal < b.sal);
+---------+
| sal |
+---------+
| 5000.00 |
+---------+
5. 取得平均薪水最高的部门的部门编号
第一种方案：降序取第一个。
第一步：找出每个部门的平均薪水
select deptno,avg(sal) as avgsal from emp group by deptno;
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
| 20 | 2175.000000 |
| 30 | 1566.666667 |
+--------+-------------+
第二步：降序选第一个。
select deptno,avg(sal) as avgsal from emp group by deptno order by avgsal desc limit 1;
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
+--------+-------------+
第二种方案：max
第一步：找出每个部门的平均薪水
select deptno,avg(sal) as avgsal from emp group by deptno;
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
| 20 | 2175.000000 |
| 30 | 1566.666667 |
+--------+-------------+
第二步：找出以上结果中 avgsal 最大的值。
select max(t.avgsal) from (select avg(sal) as avgsal from emp group by deptno) t;
+---------------+
| max(t.avgsal) |
+---------------+
| 2916.666667 |
+---------------+
第三步：
select
deptno,avg(sal) as avgsal
from
emp
group by
deptno
having
avgsal = (select max(t.avgsal) from (select avg(sal) as avgsal from emp group by deptno) t);
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
+--------+-------------+
6. 取得平均薪水最高的部门的部门名称
select
d.dname,avg(e.sal) as avgsal
from
emp e
join
dept d
on
e.deptno = d.deptno
group by
d.dname
order by
avgsal desc
limit
1;
+------------+-------------+
| dname | avgsal |
+------------+-------------+
| ACCOUNTING | 2916.666667 |
+------------+-------------+
7. 求平均薪水的等级最低的部门的部门名称
平均薪水是 800
平均薪水是 900
那么他俩都是 1 级别。
第一步：找出每个部门的平均薪水
select deptno,avg(sal) as avgsal from emp group by deptno;
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
| 20 | 2175.000000 |
| 30 | 1566.666667 |
+--------+-------------+
第二步：找出每个部门的平均薪水的等级
以上 t 表和 salgrade 表连接，条件：t.avgsal between s.losal and s.hisal
select
t.*,s.grade
from
(select d.dname,avg(sal) as avgsal from emp e join dept d on e.deptno = d.deptno group by d.dname) t
join
salgrade s
on
t.avgsal between s.losal and s.hisal;
+------------+-------------+-------+
| dname | avgsal | grade |
+------------+-------------+-------+
| SALES | 1566.666667 | 3 |
| ACCOUNTING | 2916.666667 | 4 |
| RESEARCH | 2175.000000 | 4 |
+------------+-------------+-------+
select
t.*,s.grade
from
(select d.dname,avg(sal) as avgsal from emp e join dept d on e.deptno = d.deptno group by d.dname) t
join
salgrade s
on
t.avgsal between s.losal and s.hisal
where
s.grade = (select grade from salgrade where (select avg(sal) as avgsal from emp group by deptno order by avgsal asc limit 1) between losal and hisal);
+-------+-------------+-------+
| dname | avgsal | grade |
+-------+-------------+-------+
| SALES | 1566.666667 | 3 |
+-------+-------------+-------+
抛开之前的，最低等级你怎么着？
平均薪水最低的对应的等级一定是最低的.
select avg(sal) as avgsal from emp group by deptno order by avgsal asc limit 1;
+-------------+
| avgsal |
+-------------+
| 1566.666667 |
+-------------+
select grade from salgrade where (select avg(sal) as avgsal from emp group by deptno order by avgsal asc limit 1) between losal and hisal;
+-------+
| grade |
+-------+
| 3 |
+-------+
8. 取得比普通员工(员工代码没有在 mgr 字段上出现的) 的最高薪水还要高的领导人姓名
比“普通员工的最高薪水”还要高的一定是领导！没毛病！！！！
mysql> select distinct mgr from emp where mgr is not null;
+------+
| mgr |
+------+
| 7902 |
| 7698 |
| 7839 |
| 7566 |
| 7788 |
| 7782 |
+------+
员工编号没有在以上范围内的都是普通员工。
第一步：找出普通员工的最高薪水！
not in 在使用的时候，后面小括号中记得排除 NULL。
select max(sal) from emp where empno not in(select distinct mgr from emp where mgr is not null);
+----------+
| max(sal) |
+----------+
| 1600.00 |
+----------+
第二步：找出高于 1600 的
select ename,sal from emp where sal > (select max(sal) from emp where empno not in(select distinct mgr from emp where mgr is not null));
+-------+---------+
| ename | sal |
+-------+---------+
| JONES | 2975.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| FORD | 3000.00 |
+-------+---------+
9. 取得薪水最高的前五名员工
select ename,sal from emp order by sal desc limit 5;
+-------+---------+
| ename | sal |
+-------+---------+
| KING | 5000.00 |
| SCOTT | 3000.00 |
| FORD | 3000.00 |
| JONES | 2975.00 |
| BLAKE | 2850.00 |
+-------+---------+
10. 取得薪水最高的第六到第十名员工
select ename,sal from emp order by sal desc limit 5, 5;
+--------+---------+
| ename | sal |
+--------+---------+
| CLARK | 2450.00 |
| ALLEN | 1600.00 |
| TURNER | 1500.00 |
| MILLER | 1300.00 |
| MARTIN | 1250.00 |
+--------+---------+
11. 取得最后入职的 5 名员工
日期也可以降序，升序。
select ename,hiredate from emp order by hiredate desc limit 5;
+--------+------------+
| ename | hiredate |
+--------+------------+
| ADAMS | 1987-05-23 |
| SCOTT | 1987-04-19 |
| MILLER | 1982-01-23 |
| FORD | 1981-12-03 |
| JAMES | 1981-12-03 |
+--------+------------+
12. 取得每个薪水等级有多少员工
分组 count
第一步：找出每个员工的薪水等级
select
e.ename,e.sal,s.grade
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal;
+--------+---------+-------+
| ename | sal | grade |
+--------+---------+-------+
| SMITH | 800.00 | 1 |
| ALLEN | 1600.00 | 3 |
| WARD | 1250.00 | 2 |
| JONES | 2975.00 | 4 |
| MARTIN | 1250.00 | 2 |
| BLAKE | 2850.00 | 4 |
| CLARK | 2450.00 | 4 |
| SCOTT | 3000.00 | 4 |
| KING | 5000.00 | 5 |
| TURNER | 1500.00 | 3 |
| ADAMS | 1100.00 | 1 |
| JAMES | 950.00 | 1 |
| FORD | 3000.00 | 4 |
| MILLER | 1300.00 | 2 |
+--------+---------+-------+
第二步：继续按照 grade 分组统计数量
select
s.grade ,count(*)
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal
group by
s.grade;
+-------+----------+
| grade | count(*) |
+-------+----------+
| 1 | 3 |
| 2 | 3 |
| 3 | 2 |
| 4 | 5 |
| 5 | 1 |
+-------+----------+
13. 面试题
有 3 个表 S（学生表），C（课程表），SC（学生选课表）
S（SNO，SNAME）代表（学号，姓名）
C（CNO，CNAME，CTEACHER）代表（课号，课名，教师）
SC（SNO，CNO，SCGRADE）代表（学号，课号，成绩）
问题：
- 找出没选过“黎明”老师的所有学生姓名。
- 列出 2 门以上（含 2 门）不及格学生姓名及平均成绩。
- 即学过 1 号课程又学过 2 号课所有学生的姓名。
14. 列出所有员工及其领导的姓名
select
a.ename '员工', b.ename '领导'
from
emp a
left join
emp b
on
a.mgr = b.empno;
+--------+-------+
| 员工 | 领导 |
+--------+-------+
| SMITH | FORD |
| ALLEN | BLAKE |
| WARD | BLAKE |
| JONES | KING |
| MARTIN | BLAKE |
| BLAKE | KING |
| CLARK | KING |
| SCOTT | JONES |
| KING | NULL |
| TURNER | BLAKE |
| ADAMS | SCOTT |
| JAMES | BLAKE |
| FORD | JONES |
| MILLER | CLARK |
+--------+-------+
15. 列出受雇日期早于其直接上级的所有员工的编号,姓名,部门名称
emp a 员工表
emp b 领导表
a.mgr = b.empno and a.hiredate < b.hiredate
select
a.ename '员工', a.hiredate, b.ename '领导', b.hiredate, d.dname
from
emp a
join
emp b
on
a.mgr = b.empno
join
dept d
on
a.deptno = d.deptno
where
a.hiredate < b.hiredate;
+-------+------------+-------+------------+------------+
| 员工 | hiredate | 领导 | hiredate | dname |
+-------+------------+-------+------------+------------+
| SMITH | 1980-12-17 | FORD | 1981-12-03 | RESEARCH |
| ALLEN | 1981-02-20 | BLAKE | 1981-05-01 | SALES |
| WARD | 1981-02-22 | BLAKE | 1981-05-01 | SALES |
| JONES | 1981-04-02 | KING | 1981-11-17 | RESEARCH |
| BLAKE | 1981-05-01 | KING | 1981-11-17 | SALES |
| CLARK | 1981-06-09 | KING | 1981-11-17 | ACCOUNTING |
+-------+------------+-------+------------+------------+
16. 列出部门名称和这些部门的员工信息, 同时列出那些没有员工的部门
select
e.*,d.dname
from
emp e
right join
dept d
on
e.deptno = d.deptno;
+-------+--------+-----------+------+------------+---------+---------+--------+------------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO | dname |
+-------+--------+-----------+------+------------+---------+---------+--------+------------+
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 | ACCOUNTING |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 | ACCOUNTING |
| 7934 | MILLER | CLERK | 7782 | 1982-01-23 | 1300.00 | NULL | 10 | ACCOUNTING |
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 800.00 | NULL | 20 | RESEARCH |
| 7566 | JONES | MANAGER | 7839 | 1981-04-02 | 2975.00 | NULL | 20 | RESEARCH |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 | RESEARCH |
| 7876 | ADAMS | CLERK | 7788 | 1987-05-23 | 1100.00 | NULL | 20 | RESEARCH |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 | RESEARCH |
| 7499 | ALLEN | SALESMAN | 7698 | 1981-02-20 | 1600.00 | 300.00 | 30 | SALES |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 | SALES |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 | SALES |
| 7698 | BLAKE | MANAGER | 7839 | 1981-05-01 | 2850.00 | NULL | 30 | SALES |
| 7844 | TURNER | SALESMAN | 7698 | 1981-09-08 | 1500.00 | 0.00 | 30 | SALES |
| 7900 | JAMES | CLERK | 7698 | 1981-12-03 | 950.00 | NULL | 30 | SALES |
| NULL | NULL | NULL | NULL | NULL | NULL | NULL | NULL | OPERATIONS |
+-------+--------+-----------+------+------------+---------+---------+--------+------------+
17. 列出至少有 5 个员工的所有部门
按照部门编号分组，计数，筛选出 >= 5
select
deptno
from
emp
group by
deptno
having
count(*) >= 5;
+--------+
| deptno |
+--------+
| 20 |
| 30 |
+--------+
18. 列出薪金比"SMITH" 多的所有员工信息
select ename,sal from emp where sal > (select sal from emp where ename = 'SMITH');
+--------+---------+
| ename | sal |
+--------+---------+
| ALLEN | 1600.00 |
| WARD | 1250.00 |
| JONES | 2975.00 |
| MARTIN | 1250.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| TURNER | 1500.00 |
| ADAMS | 1100.00 |
| JAMES | 950.00 |
| FORD | 3000.00 |
| MILLER | 1300.00 |
+--------+---------+
19. 列出所有"CLERK"( 办事员) 的姓名及其部门名称, 部门的人数
select ename,job from emp where job = 'CLERK';
+--------+-------+
| ename | job |
+--------+-------+
| SMITH | CLERK |
| ADAMS | CLERK |
| JAMES | CLERK |
| MILLER | CLERK |
+--------+-------+
select
e.ename,e.job,d.dname
from
emp e
join
dept d
on
e.deptno = d.deptno
where
e.job = 'CLERK';
+--------+-------+------------+
| ename | job | dname |
+--------+-------+------------+
| MILLER | CLERK | ACCOUNTING |
| SMITH | CLERK | RESEARCH |
| ADAMS | CLERK | RESEARCH |
| JAMES | CLERK | SALES |
+--------+-------+------------+
select
e.ename,e.job,d.dname,d.deptno
from
emp e
join
dept d
on
e.deptno = d.deptno
where
e.job = 'CLERK';
+--------+-------+------------+--------+
| ename | job | dname | deptno |
+--------+-------+------------+--------+
| MILLER | CLERK | ACCOUNTING | 10 |
| SMITH | CLERK | RESEARCH | 20 |
| ADAMS | CLERK | RESEARCH | 20 |
| JAMES | CLERK | SALES | 30 |
+--------+-------+------------+--------+
//每个部门的人数？
select deptno, count(*) as deptcount from emp group by deptno;
+--------+-----------+
| deptno | deptcount |
+--------+-----------+
| 10 | 3 |
| 20 | 5 |
| 30 | 6 |
+--------+-----------+
select
t1.*,t2.deptcount
from
(select
e.ename,e.job,d.dname,d.deptno
from
emp e
join
dept d
on
e.deptno = d.deptno
where
e.job = 'CLERK') t1
join
(select deptno, count(*) as deptcount from emp group by deptno) t2
on
t1.deptno = t2.deptno;
+--------+-------+------------+--------+-----------+
| ename | job | dname | deptno | deptcount |
+--------+-------+------------+--------+-----------+
| MILLER | CLERK | ACCOUNTING | 10 | 3 |
| SMITH | CLERK | RESEARCH | 20 | 5 |
| ADAMS | CLERK | RESEARCH | 20 | 5 |
| JAMES | CLERK | SALES | 30 | 6 |
+--------+-------+------------+--------+-----------+
20. 列出最低薪金大于 1500 的各种工作及从事此工作的全部雇员人数
按照工作岗位分组求最小值。
select job,count(*) from emp group by job having min(sal) > 1500;
+-----------+----------+
| job | count(*) |
+-----------+----------+
| ANALYST | 2 |
| MANAGER | 3 |
| PRESIDENT | 1 |
+-----------+----------+
21. 列出在部门"SALES"< 销售部> 工作的员工的姓名, 假定不知道销售部的部门编号.
select ename from emp where deptno = (select deptno from dept where dname = 'SALES');
+--------+
| ename |
+--------+
| ALLEN |
| WARD |
| MARTIN |
| BLAKE |
| TURNER |
| JAMES |
+--------+
22. 列出薪金高于公司平均薪金的所有员工, 所在部门, 上级领导, 雇员的工资等级.
select
e.ename '员工',d.dname,l.ename '领导',s.grade
from
emp e
join
dept d
on
e.deptno = d.deptno
left join
emp l
on
e.mgr = l.empno
join
salgrade s
on
e.sal between s.losal and s.hisal
where
e.sal > (select avg(sal) from emp);
+-------+------------+-------+-------+
| 员工 | dname | 领导 | grade |
+-------+------------+-------+-------+
| JONES | RESEARCH | KING | 4 |
| BLAKE | SALES | KING | 4 |
| CLARK | ACCOUNTING | KING | 4 |
| SCOTT | RESEARCH | JONES | 4 |
| KING | ACCOUNTING | NULL | 5 |
| FORD | RESEARCH | JONES | 4 |
+-------+------------+-------+-------+
23. 列出与"SCOTT" 从事相同工作的所有员工及部门名称
select job from emp where ename = 'SCOTT';
+---------+
| job |
+---------+
| ANALYST |
+---------+
select
e.ename,e.job,d.dname
from
emp e
join
dept d
on
e.deptno = d.deptno
where
e.job = (select job from emp where ename = 'SCOTT')
and
e.ename <> 'SCOTT';
+-------+---------+----------+
| ename | job | dname |
+-------+---------+----------+
| FORD | ANALYST | RESEARCH |
+-------+---------+----------+
24. 列出薪金等于部门 30 中员工的薪金的其他员工的姓名和薪金.
select distinct sal from emp where deptno = 30;
+---------+
| sal |
+---------+
| 1600.00 |
| 1250.00 |
| 2850.00 |
| 1500.00 |
| 950.00 |
+---------+
select
ename,sal
from
emp
where
sal in(select distinct sal from emp where deptno = 30)
and
deptno <> 30;
Empty set (0.00 sec)
25. 列出薪金高于在部门 30 工作的，员工薪金的姓名·薪金·部门名称
select max(sal) from emp where deptno = 30;
+----------+
| max(sal) |
+----------+
| 2850.00 |
+----------+
select
e.ename,e.sal,d.dname
from
emp e
join
dept d
on
e.deptno = d.deptno
where
e.sal > (select max(sal) from emp where deptno = 30);
+-------+---------+------------+
| ename | sal | dname |
+-------+---------+------------+
| KING | 5000.00 | ACCOUNTING |
| JONES | 2975.00 | RESEARCH |
| SCOTT | 3000.00 | RESEARCH |
| FORD | 3000.00 | RESEARCH |
+-------+---------+------------+
26. 列出在每个部门工作的员工数量, 平均工资和平均服务期限
没有员工的部门，部门人数是 0
select
d.deptno, count(e.ename) ecount,ifnull(avg(e.sal),0) as avgsal, ifnull(avg(timestampdiff(YEAR, hiredate, now())), 0) as avgservicetime
from
emp e
right join
dept d
on
e.deptno = d.deptno
group by
d.deptno;
+--------+--------+-------------+----------------+
| deptno | ecount | avgsal | avgservicetime |
+--------+--------+-------------+----------------+
| 10 | 3 | 2916.666667 | 38.0000 |
| 20 | 5 | 2175.000000 | 35.8000 |
| 30 | 6 | 1566.666667 | 38.3333 |
| 40 | 0 | 0.000000 | 0.0000 |
+--------+--------+-------------+----------------+
在 mysql 当中怎么计算两个日期的“年差”，差了多少年？
TimeStampDiff(间隔类型, 前一个日期, 后一个日期)
timestampdiff(YEAR, hiredate, now())
间隔类型：
SECOND 秒，
MINUTE 分钟，
HOUR 小时，
DAY 天，
WEEK 星期
MONTH 月，
QUARTER 季度，
YEAR 年
27. 列出所有员工的姓名、部门名称和工资
select
e.ename,d.dname,e.sal
from
emp e
join
dept d
on
e.deptno = d.deptno;
+--------+------------+---------+
| ename | dname | sal |
+--------+------------+---------+
| CLARK | ACCOUNTING | 2450.00 |
| KING | ACCOUNTING | 5000.00 |
| MILLER | ACCOUNTING | 1300.00 |
| SMITH | RESEARCH | 800.00 |
| JONES | RESEARCH | 2975.00 |
| SCOTT | RESEARCH | 3000.00 |
| ADAMS | RESEARCH | 1100.00 |
| FORD | RESEARCH | 3000.00 |
| ALLEN | SALES | 1600.00 |
| WARD | SALES | 1250.00 |
| MARTIN | SALES | 1250.00 |
| BLAKE | SALES | 2850.00 |
| TURNER | SALES | 1500.00 |
| JAMES | SALES | 950.00 |
+--------+------------+---------+
28. 列出所有部门的详细信息和人数
select
d.deptno,d.dname,d.loc,count(e.ename)
from
emp e
right join
dept d
on
e.deptno = d.deptno
group by
d.deptno,d.dname,d.loc;
+--------+------------+----------+----------------+
| deptno | dname | loc | count(e.ename) |
+--------+------------+----------+----------------+
| 10 | ACCOUNTING | NEW YORK | 3 |
| 20 | RESEARCH | DALLAS | 5 |
| 30 | SALES | CHICAGO | 6 |
| 40 | OPERATIONS | BOSTON | 0 |
+--------+------------+----------+----------------+
29. 列出各种工作的最低工资及从事此工作的雇员姓名
select
job,min(sal) as minsal
from
emp
group by
job;
+-----------+----------+
| job | minsal |
+-----------+----------+
| ANALYST | 3000.00 |
| CLERK | 800.00 |
| MANAGER | 2450.00 |
| PRESIDENT | 5000.00 |
| SALESMAN | 1250.00 |
+-----------+----------+
emp e 和以上 t 连接
select
e.ename,t.*
from
emp e
join
(select
job,min(sal) as minsal
from
emp
group by
job) t
on
e.job = t.job and e.sal = t.minsal;
+--------+-----------+---------+
| ename | job | minsal |
+--------+-----------+---------+
| SMITH | CLERK | 800.00 |
| WARD | SALESMAN | 1250.00 |
| MARTIN | SALESMAN | 1250.00 |
| CLARK | MANAGER | 2450.00 |
| SCOTT | ANALYST | 3000.00 |
| KING | PRESIDENT | 5000.00 |
| FORD | ANALYST | 3000.00 |
+--------+-----------+---------+
30. 列出各个部门的 MANAGER(领导) 的最低薪金
select
deptno, min(sal)
from
emp
where
job = 'MANAGER'
group by
deptno;
+--------+----------+
| deptno | min(sal) |
+--------+----------+
| 10 | 2450.00 |
| 20 | 2975.00 |
| 30 | 2850.00 |
+--------+----------+
31. 列出所有员工的 年工资, 按 年薪从低到高排序
select
ename,(sal + ifnull(comm,0)) * 12 as yearsal
from
emp
order by
yearsal asc;
+--------+----------+
| ename | yearsal |
+--------+----------+
| SMITH | 9600.00 |
| JAMES | 11400.00 |
| ADAMS | 13200.00 |
| MILLER | 15600.00 |
| TURNER | 18000.00 |
| WARD | 21000.00 |
| ALLEN | 22800.00 |
| CLARK | 29400.00 |
| MARTIN | 31800.00 |
| BLAKE | 34200.00 |
| JONES | 35700.00 |
| FORD | 36000.00 |
| SCOTT | 36000.00 |
| KING | 60000.00 |
+--------+----------+
32. 求出员工领导的薪水超过 3000 的员工名称与领导
select
a.ename '员工',b.ename '领导'
from
emp a
join
emp b
on
a.mgr = b.empno
where
b.sal > 3000;
+-------+------+
| 员工 | 领导 |
+-------+------+
| JONES | KING |
| BLAKE | KING |
| CLARK | KING |
+-------+------+
33. 求出部门名称中, 带’S’字符的部门员工的工资合计、部门人数
select
d.deptno,d.dname,d.loc,count(e.ename),ifnull(sum(e.sal),0) as sumsal
from
emp e
right join
dept d
on
e.deptno = d.deptno
where
d.dname like '%S%'
group by
d.deptno,d.dname,d.loc;
+--------+------------+---------+----------------+----------+
| deptno | dname | loc | count(e.ename) | sumsal |
+--------+------------+---------+----------------+----------+
| 20 | RESEARCH | DALLAS | 5 | 10875.00 |
| 30 | SALES | CHICAGO | 6 | 9400.00 |
| 40 | OPERATIONS | BOSTON | 0 | 0.00 |
+--------+------------+---------+----------------+----------+
34. 给任职日期超过 30 年的员工加薪 10%.
update emp set sal = sal * 1.1 where timestampdiff(YEAR, hiredate, now()) > 30;