Part 2 of 2 Two‘s complement

Part 2 of 2 Two‘s complement

Part 2 of 2 Two‘s complement

学号16340090
int8_t x = -0x1f = 10011111
int y = x = 159
因为x=−16−15=−31=（10011111）2 补码为（11100001）2转化为十六进制为（1b1）16
所以y=128+16+8+4+2+1=159转化为十六进制为（09f）16