OJ:一道考察多态的题目

Description

下面程序的输出结果是:

A::Fun

C::Do

程序代码

#include <iostream>
using namespace std;

class A {
    private:
        int nVal;
    public:
        void Fun()
        { cout << "A::Fun" << endl; }
        void Do()
        { cout << "A::Do" << endl; }
};

class B:public A {
    public:
        virtual void Do()
        { cout << "B::Do" << endl; }
};

class C:public B {
    public:
        void Do( )
        { cout << "C::Do" <<endl; }
        void Fun()
        { cout << "C::Fun" << endl; }
};

/* 括号内所填为该题答案 */
void Call(B& p)
{
    p.Fun();  
    p.Do();
}

int main() 
{
    C c;    
    Call(c);
    
    return 0;
}

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转载自www.cnblogs.com/GyForever1004/p/9157097.html