# coding: utf-8
class Solution(object):
def reverse_num(self, num):
hundreds = num/100
tens = num % 100/10
ones = num % 10
return ones*100 + tens*10 + hundreds
if __name__ == '__main__':
solution = Solution()
num = solution.reverseNum(800)
print (num)
[Python编程300例]例1 反转一个3位整数
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转载自blog.csdn.net/weixin_45329445/article/details/116035349
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