求nums的动态和

示例:

输入:[1,2,3,4]

输出:[1,3,6,10]

class Solution(object):
    def runningSum(self, nums):
        a=[0]*len(nums)
        for i in range(len(nums)):
            a[i]=sum(nums[:i+1])
        return a

a=Solution()
print(a.runningSum([1,2,3,4]))

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转载自blog.csdn.net/Tinyfacture/article/details/131828572