C#求质数

            for (int i = 2; i <= 10000; i++)
            {
                bool isPrimeNUmber = true;  
                for (int j = 2; j < i - 1; j++)
                {
                    if (i % j == 0)
                    {
                        isPrimeNUmber = false;
                        break;
                    }
                }
                if (isPrimeNUmber)
                {
                    count++;
                }
            }

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转载自blog.csdn.net/Danelxiong/article/details/129335927