JavaScript中判断一个元素是否在列表

在JavaScript中判断一个元素是否在列表中,有几种常用的方法:

# 1、使用数组的includes()方法:

const list = [1, 2, 3];

if (list.includes(2)) {
    console.log('2 is in the list');
}


# 2、使用数组的indexOf()方法,判断返回的索引是否不为-1:

const list = [1, 2, 3]; 
if (list.indexOf(2) !== -1) { 
    console.log('2 is in the list'); 
}

# 3、使用数组的some()方法,查找是否有满足条件的元素:

const list = [1, 2, 3]; 
if (list.some(item => item === 2)) { 
    console.log('2 is in the list'); 
}


# 4、使用Set的has()方法,将列表转换为Set后查找:

const list = [1, 2, 3]; 
const set = new Set(list); 
if (set.has(2)) { console.log('2 is in the list'); }


# 5、使用indexOf()配合从后往前找:

const list = [1, 2, 3, 2]; 
if (list.indexOf(2, list.length - 1) !== -1) { 
    console.log('2 is in the list'); 
}

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转载自blog.csdn.net/bulucc/article/details/132046286