Python遍历文件夹下的文件并根据要求时间进行删除

遍历指定路径下的文件夹下文件,并根据文件生成时间与现有时间比较,设置相应的时间进行删除文件

import os  
import datetime
import shutil

def gci(base):
    #base = 'C:\\robotframework\\logs'
    #output_dir = os.path.join(base, 'logs', datetime.datetime.now().strftime('%Y%m%d'),datetime.datetime.now().strftime('%H-%M-%S'))
    listdir = os.listdir(base)
    #print listdir
    
    
    now = datetime.datetime.now()
    #minutes\hours
    delta = datetime.timedelta(hours=1) 
    for i in range(len(listdir)):  
        dir = os.path.join(base,listdir[i])
        #print dir    
        dir1 = os.listdir(dir)
        #print dir1
        for j in range(len(dir1)):
            dir2 =dir1[j]
            #print dir2
            dir3 = os.path.join(dir,dir2)
            #print dir3        
            #dir2 = os.path.join(dir,dir1[j])
            #print dir2
            #dir3 = os.listdir(dir2)
            #print dir3
            #ctime= datetime.datetime.fromtimestamp(os.path.getctime(os.path.join(dir,dir2)))
            ctime= datetime.datetime.fromtimestamp(os.path.getctime(dir3))
            print ctime
            
            if ctime < (now - delta):
                shutil.rmtree(dir3)
            else:
                print dir3 + ': is not needed to be removed!'
                #os.chdir(dir)
                #shutil.rmtree(dir2) 
#递归遍历base目录下所有文件
gci('C:\\robotframework\\logs')   

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转载自blog.csdn.net/tjfsuxyy/article/details/87916038
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