Tomcat容器快速部署SpringBoot项目（war包形式）

springboot项目可以直接启动主类即可，但是线上的项目一般都会放在容器里面run，因此记录下我在开发中是如何将springboot项目打包成war包形式部署在tomcat中的。

1、添加spring-boot-starter-tomcat依赖

<packaging>war</packaging>

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-tomcat</artifactId>
    <scope>provided</scope>
</dependency>

2、添加maven-war-plugin依赖

<build>
       <finalName>${project.artifactId}</finalName>
       <plugins>
              <plugin>
                     <groupId>org.apache.maven.plugins</groupId>
                     <artifactId>maven-war-plugin</artifactId>
                     <configuration>
                           <failOnMissingWebXml>false</failOnMissingWebXml>
                     </configuration>
              </plugin>
       </plugins>
</build>

3、修改启动类继承SpringBootServletInitializer

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.builder.SpringApplicationBuilder;
import org.springframework.boot.web.support.SpringBootServletInitializer;

@SpringBootApplication
public class MainApplication extends SpringBootServletInitializer{
       public static void main(String[] args) {
              SpringApplication.run(MainApplication.class, args);
       }

       @Override
       protected SpringApplicationBuilder configure(SpringApplicationBuilder builder) {
              return builder.sources(MainApplication.class);
       }
}

4、注意Tomcat中运行项目war是否含根路径，同时注意application.yml配置文件中是否添加了

server:
  port: 8888
  servlet:
    context-path: /root    ##看看是否设置了context-path

5、intellij idea中直接在maven projects窗口的lifecycle下点击package打包或者进入项目本地路径执行命令

mvn clean package -Dmaven.test.skip=true

6、具体的tomcat部署war参考下图: