leetcode+ 有序链表删除相同元素

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class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        ListNode* root = head;
        while (head != NULL) {
            /*下一节点存在，且当前节点和下一节点的值重复*/
            while (head->next != NULL && head->val == head->next->val) {
                head->next = head->next->next;
            }
            head = head->next;
        }
        return root;
    }
};