UVA - 1588 换低挡装置

思路:模拟题 注意下标i+j 和j的对应字符串的匹配关系  注意要模拟从最左边到最右边 

刚开始做莫名其妙WA,检查不出错误,后面重写了才过的

AC代码:

#include<cstring>
#include<iostream>
#include<cstdio>
using namespace std;
char s1[105],s2[105];  //用字符串读方便

int main(){
while(cin>>s1>>s2){
    int a=strlen(s1),b=strlen(s2);
    int chongdie=0;
    int minnum=10000000;
       if(a<b){
            char temp[105];
        memcpy(temp,s1,sizeof(s1));
       memcpy(s1,s2,sizeof(s1));
       memcpy(s2,temp,sizeof(s1));

       a=strlen(s1);
       b=strlen(s2);
       }
       for(int i=-b;i<=a;i++){
            int flag=0;
        for(int j=0;j<b;j++){
            if(j+i>=0&&i+j<a){
                if(s1[j+i]+s2[j]-'0'>'3'){    
                    flag=1;
                    break;
                }
            }

        }
         if(!flag&&i<0){
                minnum=min(-i+a,minnum);
            }
            else if(!flag&&i>a-b){
                minnum=min(i+b,minnum);
            }
            else if(!flag&&i>=0&&i<=a-b){   //此时为最小值
                chongdie=1;
                break;
            }

       }
       if(chongdie)printf("%d\n",a);
       else printf("%d\n",minnum);
}
return 0;
}

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转载自blog.csdn.net/bug___maker/article/details/80025087
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