Gson使用三(集合的处理,一对多处理)

转载请出自出处：http://eksliang.iteye.com/blog/2175532

一、概述

       Map保存的是键值对的形式，Json的格式也是键值对的，所以正常情况下，map跟json之间的转换应当是理所当然的事情。

二、Map参考实例

package com.ickes.json;

import java.lang.reflect.Type;
import java.util.ArrayList;
import java.util.Date;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.google.gson.reflect.TypeToken;
import com.ickes.json.daomain.User;
/**
 * Gson对Map的处理
 * @author Ickes
 *
 */
public class MapTest {
	public static void main(String[] args) {
		/**
		 * 普通map处理
		 */
		Map<String,String> map = new HashMap<String,String>();
		map.put("name","ickes");
		map.put("pwd", "123");
		Gson gson = new GsonBuilder()
		.enableComplexMapKeySerialization()
		.setPrettyPrinting()
		.setDateFormat("yyyy-MM-dd HH:mm:ss")
		.create();
		//map的序列化
		String json=gson.toJson(map);
		System.out.println("map的序列化：\n"+json);
		//map的反序列化
		Type typeMap = new TypeToken<Map<String,String>>(){}.getType();
		map = gson.fromJson(json,typeMap);
		System.out.println("map的反序列化:");
		for (Map.Entry<String,String> entry: map.entrySet()) {
			System.out.println(entry.getKey()+"-"+entry.getValue());
		}
		
		/**
		 * /map对象测试
		 */
		Map<String,User> mapUser = new HashMap<String,User>();
		User user1 = new User("A001", "xl","xl_123",24,12000F,new Date());
		User user2 = new User("A002", "x2","xl_223",24,13000F,new Date());
		mapUser.put("user1",user1);
		mapUser.put("user2",user2);
		json = gson.toJson(mapUser);
		System.out.println("Map对象的序列化:\n"+json);
		//map对象的反序列化
		Type typeUser = new TypeToken<Map<String,User>>(){}.getType();
		mapUser = gson.fromJson(json, typeUser);
		System.out.println("map对象的反序列化:");
		for (Map.Entry<String,User> entry: mapUser.entrySet()) {
			System.out.println(entry.getKey()+"-"+entry.getValue());
		}
		
		/**
		 * 整合测试
		 */
		Map<String,List<User>> mapList = new HashMap<String,List<User>>();
		List<User> users = new ArrayList<User>();
		users.add(user1);
		users.add(user2);
		mapList.put("mapList",users);
		//序列化
		json = gson.toJson(mapList);
		System.out.println("mapList的序列化：\n"+json);
		//反序列化
		Type typeMapList = new TypeToken<Map<String,List<User>>>(){}.getType();
		mapList = gson.fromJson(json, typeMapList);
		System.out.println("mapList对象的反序列化:");
		for (Map.Entry<String,List<User>> entry: mapList.entrySet()) {
			System.out.println(entry.getKey()+"-"+entry.getValue());
		}
	}
}

 返回结果：

map的序列化：
{
  "pwd": "123",
  "name": "ickes"
}
map的反序列化:
pwd-123
name-ickes
Map对象的序列化:
{
  "user2": {
    "id": "A002",
    "userName": "x2",
    "userPwd": "xl_223",
    "age": 24,
    "price": 13000.0,
    "birthday": "2015-01-13 16:06:48"
  },
  "user1": {
    "id": "A001",
    "userName": "xl",
    "userPwd": "xl_123",
    "age": 24,
    "price": 12000.0,
    "birthday": "2015-01-13 16:06:48"
  }
}
map对象的反序列化:
user2-User [id=A002, userName=x2, userPwd=xl_223, age=24, price=13000.0, birthday=Tue Jan 13 16:06:48 CST 2015]
user1-User [id=A001, userName=xl, userPwd=xl_123, age=24, price=12000.0, birthday=Tue Jan 13 16:06:48 CST 2015]
mapList的序列化：
{
  "mapList": [
    {
      "id": "A001",
      "userName": "xl",
      "userPwd": "xl_123",
      "age": 24,
      "price": 12000.0,
      "birthday": "2015-01-13 16:06:48"
    },
    {
      "id": "A002",
      "userName": "x2",
      "userPwd": "xl_223",
      "age": 24,
      "price": 13000.0,
      "birthday": "2015-01-13 16:06:48"
    }
  ]
}
mapList对象的反序列化:
mapList-[User [id=A001, userName=xl, userPwd=xl_123, age=24, price=12000.0, birthday=Tue Jan 13 16:06:48 CST 2015], User [id=A002, userName=x2, userPwd=xl_223, age=24, price=13000.0, birthday=Tue Jan 13 16:06:48 CST 2015]]

         温馨提示：Gson在序列化Map时，默认情况下，是调用Key的toString方法得到它的JSON字符串的Key，对于简单类型和字符串类型，这没有问题，但是对于复杂数据对象，如果对象没有覆写toString方法，那么默认的toString方法将得到这个对象的Hash地址，通过调用GsonBuilder的enableComplexMapKeySerialization()来启用对Map键（key）的序列化.

 

 

 

三、一对多参考实例

下面实例提供了User(员工)对Dept(部门)一对多的映射关系

User实体类：

package com.ickes.json.daomain;

import java.util.Date;

/**
 * @author Ickes
 */
public class User {
	private String userName;
	private String userPwd;
	private Integer age;
	private Date    birthday;
	
	public User(String userName, String userPwd, Integer age, Date birthday) {
		super();
		this.userName = userName;
		this.userPwd = userPwd;
		this.age = age;
		this.birthday = birthday;
	}
	get()和set()方法省略.....!
	@Override
	public String toString() {
		return "User [userName=" + userName + ", userPwd=" + userPwd + ", age="
				+ age + ", birthday=" + birthday + "]";
	}
	
}

    Dept实体类：

   

package com.ickes.json.daomain;

import java.util.List;

public class Dept {
	private String id;
	private String deptName;
	private List<User> users;
	
	public Dept(String id, String deptName) {
		super();
		this.id = id;
		this.deptName = deptName;
	}
	get()和set()方法省略......!
	@Override
	public String toString() {
		return "Dept [id=" + id + ", deptName=" + deptName + ", users=" + users
				+ "]";
	} 
	
	
}

    测试实体类：

   

package com.ickes.json.daomain;

import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
/**
 * Gson处理这种一对多的序列化
 * @author Ickes
 *
 */
public class DeptTest {
	public static void main(String[] args) {
		User user1 = new User("xl","xl_223",12100,new Date());
		User user2 = new User("x2","xl_323",12300,new Date());
		User user3 = new User("x3","xl_423",12300,new Date());
		Dept dept = new Dept("D001","技术预研部");
		List<User> users = new ArrayList<User>();
		users.add(user1);
		users.add(user2);
		users.add(user3);
		dept.setUsers(users);
		
		Gson gson = new GsonBuilder()
		.setPrettyPrinting()
		.setDateFormat("yyyy-MM-dd HH:mm:ss")
		.create();
		String json=gson.toJson(dept);
		System.out.println("一对多的序列化:\n"+json);
		
		dept = gson.fromJson(json,Dept.class);
		System.out.println("一对多的反序列化：\n"+dept);
		
	}
}

   返回结果如下：

一对多的序列化:
{
  "id": "D001",
  "deptName": "技术预研部",
  "users": [
    {
      "userName": "xl",
      "userPwd": "xl_223",
      "age": 12100,
      "birthday": "2015-01-13 18:57:23"
    },
    {
      "userName": "x2",
      "userPwd": "xl_323",
      "age": 12300,
      "birthday": "2015-01-13 18:57:23"
    },
    {
      "userName": "x3",
      "userPwd": "xl_423",
      "age": 12300,
      "birthday": "2015-01-13 18:57:23"
    }
  ]
}
一对多的反序列化：
Dept [id=D001, deptName=技术预研部, 
users=[User [userName=xl, userPwd=xl_223, age=12100, birthday=Tue Jan 13 18:57:23 CST 2015], 
       User [userName=x2, userPwd=xl_323, age=12300, birthday=Tue Jan 13 18:57:23 CST 2015],
       User [userName=x3, userPwd=xl_423, age=12300, birthday=Tue Jan 13 18:57:23 CST 2015]
       ]]

 

 四、带泛型的list集合处理

public static void main(String[] args) {
		Gson gson = new Gson();
		String json="[{'last':'xiao','next':'ming'},{'last':'xiao','next':'liang'}]";
		List<Dept> list= null;
		list = gson.fromJson(json,new TypeToken<List<Dept>>(){}.getType());
		for (Dept dept : list) {
			System.out.println(dept);
		}
	}

 返回结果如下：

Dept [last=xiao, next=ming]
Dept [last=xiao, next=liang]