bzoj 4198 [ Noi 2015 ] 荷马史诗 —— 哈夫曼编码(k叉哈夫曼树)

题目:https://www.lydsy.com/JudgeOnline/problem.php?id=4198

第一次写哈夫曼树!看了很多博客。

哈夫曼树 & 哈夫曼编码:https://www.cnblogs.com/xidongyu/p/6031518.html

这道题:http://www.cnblogs.com/LadyLex/p/7503173.html

满 k 叉树节点数的判断:https://blog.csdn.net/cqbzwja/article/details/46974241

           https://blog.csdn.net/morestep/article/details/47665135

真美啊!

代码如下:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
using namespace std;
typedef long long ll;
int n,k;
struct N{
    ll w,dep;
    N(ll w=0,int d=0):w(w),dep(d) {}
    bool operator < (const N &y) const
    {
        return w==y.w?dep>y.dep:w>y.w;
    }
}ans;
priority_queue<N>q;
int main()
{
    scanf("%d%d",&n,&k); ll x;
    for(int i=1;i<=n;i++)
    {
        scanf("%lld",&x);
        q.push(N(x,1));
    }
    while(k>2&&n%(k-1)!=1)q.push(N(0,1)),n++;
    while(q.size()>1)
    {
        N nw; nw.w=nw.dep=0;
        for(int i=1;i<=k;i++)
        {
            N t=q.top(); q.pop();
            nw.w+=t.w; nw.dep=max(nw.dep,t.dep+1);
        }
        ans.w+=nw.w; ans.dep=max(ans.dep,nw.dep);
        q.push(nw);
    }
    printf("%lld\n%d\n",ans.w,ans.dep-1);
    return 0;
}

猜你喜欢

转载自www.cnblogs.com/Zinn/p/9400381.html