两个辅助指针变量挖字符串

#define  _CRT_SECURE_NO_WARNINGS 
#include <stdlib.h>
#include <string.h>
#include <stdio.h>

//有一个字符串符合以下特征（”abcdef,acccd,eeee,aaaa,e3eeeee,sssss,";）


//分清楚赋值指针变量 和 操作逻辑之间的关系
int spitString(const char *buf1, char c, char buf2[10][30], int *count)
{
    //strcpy(buf2[0], "aaaaa");
    //strcpy(buf2[1], "bbbbbb");
    char *p=NULL, *pTmp = NULL;
    int    tmpcount = 0;

    //1 p和ptmp初始化
    p = buf1;
    pTmp = buf1;

    do 
    {
        //2 检索符合条件的位置 p后移  形成差值 挖字符串
        p = strchr(p, c);
        if (p != NULL)
        {
            if (p-pTmp > 0)
            {
                strncpy(buf2[tmpcount], pTmp,  p-pTmp);
                buf2[tmpcount][p-pTmp]  = '\0';  //把第一行数据变成 C风格字符串
                tmpcount ++;
                //3重新 让p和ptmp达到下一次检索的条件
                pTmp = p = p + 1;
            }
        }
        else
        {
            break;
        }
    } while (*p!='\0');
    
    *count = tmpcount;
    return 0;
}

void main()
{
    int ret = 0, i = 0;
    char *p1 = "abcdef,acccd,eeee,aaaa,e3eeeee,sssss,";
    char cTem= ',';
    int nCount;

    char myArray[10][30];

    ret = spitString(p1, cTem, myArray, &nCount);
    if (ret != 0)
    {
        printf("fucn spitString() err: %d \n", ret);
        return ret;
    }

    for (i=0; i<nCount; i++ )
    {
        printf("%s \n", myArray[i]);
    }
    printf("hello...\n");
    system("pause");
    return ;
}



//作业 用第三种内存模型求解问题
/*
int spitString2(const char *buf1, char c, char ***pp, int *count)
{
    
}


char ** spitString3(const char *buf1, char c, int *count)
{

}
*/