Every girl likes shopping,so does dandelion.Now she finds the shop is increasing the price every day because the Spring Festival is coming .She is fond of a shop which is called "memory". Now she wants to know the rank of this shop's price after the change of everyday.
Input
One line contians a number n ( n<=10000),stands for the number of shops.
Then n lines ,each line contains a string (the length is short than 31 and only contains lowercase letters and capital letters.)stands for the name of the shop.
Then a line contians a number m (1<=m<=50),stands for the days .
Then m parts , every parts contians n lines , each line contians a number s and a string p ,stands for this day ,the shop p 's price has increased s.
Output
Contains m lines ,In the ith line print a number of the shop "memory" 's rank after the ith day. We define the rank as :If there are t shops' price is higher than the "memory" , than its rank is t+1.
Sample Input
3 memory kfc wind 2 49 memory 49 kfc 48 wind 80 kfc 85 wind 83 memory
Sample Output
1 2
注意英语,price has increased s. 是价格增加了s,并不是增加到。增加到是increase to
其他的就是map的用法了
#include <iostream>
#include <map>
using namespace std;
//map<string ,int> shop;//默认按key排序
typedef map <string,int> mp;
mp shop;
void fun()
{
// map <string,int> ::iterator it 这个也可以
mp::iterator it;//迭代器的使用
string s="memory";
int val;
for(it=shop.begin(); it!=shop.end(); it++)
{
if(it->first ==s) val= it->second;
}
int ans1=0;
for(it=shop.begin(); it!=shop.end(); it++)
{
if(it->second > val && it->first!=s)
ans1++;
}
cout<<ans1+1<<endl;
}
int main()
{
int n,val,day;
string s;
while(cin>>n)
{
shop.clear();
for(int i=0; i<n; i++)
{
cin>>s;
shop[s]=0;//默认为零,这句也可以不要
}
cin>>day;
for(int i=0; i<day; i++)
{
for(int j=0; j<n; j++)
{
cin>>val>>s;
shop[s]+=val;
}
fun();
}
}
return 0;
}