关于android 微信一次性订阅消息接入问题

环境都已经接入，发送一次性订阅消息授权：

 final IWXAPI api = WXAPIFactory.createWXAPI(SettingActivity.this, response.getAppId());
                // 将该app注册到微信
                api.registerApp(ServerUrls.WEIXIN_APP_ID);
                Log.i("20180228", "come to send request with subscribeMessage....");
                SubscribeMessage.Req req = new SubscribeMessage.Req();
                req.templateID = response.getTemplateId();
                req.scene = 889;
//                req.reserved = response.getReserved();
                Log.i("20180228", "req.appId: "+response.getAppId());
                Log.i("20180228", "req.templateId: "+req.templateID);
//                Log.i("20180228", "req.scene: "+req.scene);
//                Log.i("20180228", "req.reserved: "+req.reserved);
                Log.i("20180228", "before send request: "+req.toString());
                boolean sendResult = api.sendReq(req);
                Log.i("20180228", "after send request: "+sendResult);
                ToastUtils.show(SettingActivity.this, "发送请求结束");

在授权页面的回调中做简单的处理：

@Override
    public void onResp(BaseResp resp) {
        Log.i("20180228", "here come to the resp with wechat request: "+resp.toString());
        Log.i("20180228", "here come to the resp with wechat errCode: "+resp.errCode);
        Log.i("20180228", "here come to the resp with wechat errStr: "+resp.errStr);
        Log.i("20180228", "here come to the resp with wechat openId: "+resp.openId);
        Log.i("20180228", "here come to the resp with wechat type: "+resp.getType());
        ToastUtils.show(this, "openId: "+resp.openId);
        if(resp.getType() == ConstantsAPI.COMMAND_SUBSCRIBE_MESSAGE){
            Log.i("20180305", "here come to resp method successful....");
        }
//        if (resp.getType() == ConstantsAPI.COMMAND_SENDAUTH && resp.errCode == BaseResp.ErrCode.ERR_OK){
//            ToastUtils.show(this, "request auth here ....");
//            String openId = resp.openId;
//            int errCode = resp.errCode;
//            String errString = resp.errStr;
//
//            new UserManager(this).bidnWXRSS(openId, new SimpleCallback<ApiResponse>() {
//                @Override
//                public void onSuccess(ApiResponse response) {
//                    ToastUtils.show(WXEntryActivity.this, "绑定成功!");
//                    finish();
//                }
//            });
//        }


        finish();
    }

在打开的调试打印中显示：

03-05 17:46:00.967 10706-10706/com.xxx I/MicroMsg.SDK.WXApiImplV10: handleIntent, cmd = 4
03-05 17:46:00.967 10706-10706/com.xxx I/MicroMsg.SDK.WXMediaMessage: pathOldToNew, oldPath = com.tencent.mm.sdk.openapi.WXAppExtendObject
03-05 17:46:00.967 10706-10706/com.xxx I/MicroMsg.SDK.WXApiImplV10: handleWxInternalRespType, extInfo = wx_internal_resptype=subscribemessage&openid=oerX_woJRjvv8NzuUJHcKJe5PzwU&template_id=H0tXdBxs_ea5bVofycFBUPZl3hRgLWHxJIVBEYhSnxQ&action=confirm&reserved=null&scene=889
03-05 17:46:00.967 10706-10706/com.xxx I/MicroMsg.SDK.WXApiImplV10: handleWxInternalRespType, respType = null
03-05 17:46:00.967 10706-10706/com.xxx E/MicroMsg.SDK.WXApiImplV10: handleWxInternalRespType fail, respType is null

handleIntent()的时候，返回的是false，也没法调用onResp方法，其中的原因是因为上面的respType = null，但是上面发现extInfo是有数据的，并且可以看出wx_internal_resptype=subscribemessage。

这边查看WXApiImplV10.class，部分代码如下：

也就是说，这边的respType=subscribemessage，但是上面解析出来变成了null，其中关键的代码是：

然后才明白，这边的extInfo字符串的起始处少了一个“?”，所以把extInfo解析成Uri后，就找不到指定的“wx_internal_resptype”属性了。所以页面会卡在WXEntryActivity页面没有进行下一步的操作，这边希望微信开发团队可以尽早处理！

对于问题的处理，感谢4，5楼 C友的意见。

关于android 微信一次性订阅消息 接入 问题

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