对Group By 语句的一次优化过程(hellodba)

生产环境中发现一条语句很慢,拿回来一看,其实是一个简单的Group By语句:

表CCMMT的数据量比较大,5M多条记录。

 

1、
SQL> select CDE, CID
  2  from CCMMT
  3  GROUP BY CDE, CID
  4  having max(ADT) < sysdate - 180;
 
707924 rows selected.
 
Elapsed: 00:06:17.49
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=414 Card=238583 Bytes=4771660)
   1    0   FILTER
   2    1     SORT (GROUP BY NOSORT) (Cost=414 Card=238583 Bytes=4771660)
   3    2       TABLE ACCESS (BY INDEX ROWID) OF 'CCMMT' (Cost=414 Card=57969096 Bytes=1159381920)
   4    3         INDEX (FULL SCAN) OF 'CCMMT_TEMP_IDX' (NON-UNIQUE) (Cost=26 Card=57969096)
 
Statistics
----------------------------------------------------------
          0  recursive calls
          0  db block gets
    2769177  consistent gets
    1089991  physical reads
          0  redo size
   23926954  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          0  sorts (memory)
          0  sorts (disk)
     707924  rows processed

 

要6min多返回。尝试调整语句写法,用minus代替Group By:

 

2、

SQL> select DISTINCT CDE, CID
  2  from CCMMT
  3  where ADT < sysdate - 180
  4  minus
  5  select DISTINCT CDE, CID
  6  from CCMMT
  7  where ADT >= sysdate - 180;
 
707924 rows selected.
 
Elapsed: 00:00:21.53
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=190624 Card=2794940
          Bytes=111797600)
   1    0   MINUS
   2    1     SORT* (UNIQUE) (Cost=95312 Card=2794940 Bytes=55898800)                                               :Q13049001
   3    2       INDEX* (FAST FULL SCAN) OF 'CCMMT_UQ1' (UNIQUE) (Cost=77305 Card=2898455 Bytes=57969100)    :Q13049000
   4    1     SORT* (UNIQUE) (Cost=95312 Card=2794940 Bytes=55898800)                                               :Q13050001
   5    4       INDEX* (FAST FULL SCAN) OF 'CCMMT_UQ1' (UNIQUE) (Cost=77305 Card=2898455 Bytes=57969100)    :Q13050000
 
   2 PARALLEL_TO_SERIAL            SELECT DISTINCT C0 C0,C1 C1 FROM :Q13049000 ORDER BY C0,C1
   3 PARALLEL_TO_PARALLEL          SELECT /*+ INDEX_RRS(A1 "CCMMT_UQ1")*/ A1."CDE" C0,A1."CA
   4 PARALLEL_TO_SERIAL            SELECT DISTINCT C0 C0,C1 C1 FROM :Q13050000 ORDER BY C0,C1
   5 PARALLEL_TO_PARALLEL          SELECT /*+ INDEX_RRS(A1 "CCMMT_UQ1")*/ A1."CDE" C0,A1."CA
 
Statistics
----------------------------------------------------------
          0  recursive calls
         33  db block gets
     126566  consistent gets
     129243  physical reads
          0  redo size
   18461368  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          4  sorts (memory)
          2  sorts (disk)
     707924  rows processed


 

效果不错,Consistent gets 和 Physical Reads都下降了,同时只需要21s就返回了。但从查询计划看,用到了并行查询,因此会消耗更多的CPU。

在(ADT, CDE, CID )上创建索引,再次执行:

 

3、

SQL> select DISTINCT CDE, CID
  2  from CCMMT
  3  where ADT < sysdate - 180
  4  minus
  5  select DISTINCT CDE, CID
  6  from CCMMT
  7  where ADT >= sysdate - 180;
 
707924 rows selected.
 
Elapsed: 00:00:26.94
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=36018 Card=2794940 Bytes=111797600)
   1    0   MINUS
   2    1     SORT (UNIQUE) (Cost=18009 Card=2794940 Bytes=55898800)
   3    2       INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
   4    1     SORT (UNIQUE) (Cost=18009 Card=2794940 Bytes=55898800)
   5    4       INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
 
Statistics
----------------------------------------------------------
          0  recursive calls
        118  db block gets
      22565  consistent gets
      31604  physical reads
          0  redo size
   18461368  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          1  sorts (memory)
          1  sorts (disk)
     707924  rows processed


 

效果也比较理想,consistent gets和physical reads再次大大下降,返回时间和上面差不多,在一个数量级上,但是不再使用并行查询了。

用NOT Exists代替minus:

 

4、

SQL> select DISTINCT CDE, CID
  2  from CCMMT a
  3  where ADT < sysdate - 180
  4  AND NOT EXISTS
  5  (SELECT CDE, CID FROM
  6  (select DISTINCT CDE, CID
  7  from CCMMT
  8  where ADT >= sysdate - 180) b
  9  WHERE a.CDE = b.CDE
 10  AND a.CID = b.CID);
 
707924 rows selected.
 
Elapsed: 00:10:35.70
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=600 Card=144923 Bytes=2898460)
   1    0   SORT (UNIQUE) (Cost=600 Card=144923 Bytes=2898460)
   2    1     INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE)(Cost=2 Card=144923 Bytes=2898460)
   3    2       TABLE ACCESS (BY INDEX ROWID) OF 'CCMMT' (Cost=2 Card=1 Bytes=20)
   4    3         INDEX (RANGE SCAN) OF 'CCMMT_TEMP_IDX' (NON-UNIQUE) (Cost=1 Card=9)
 
Statistics
----------------------------------------------------------
          5  recursive calls
        118  db block gets
   40535587  consistent gets
    3157604  physical reads
          0  redo size
   18461368  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          2  sorts (memory)
          1  sorts (disk)
     707924  rows processed
 
FT! consistent gets和physical reads爆涨,10min才返回结果!
用Not In换掉Not Exists:


 

5、

SQL> select DISTINCT CDE, CID
  2  from CCMMT a
  3  where ADT < sysdate - 180
  4  AND (CDE, CID) NOT IN
  5  (select DISTINCT CDE, CID
  6  from CCMMT
  7  where ADT >= sysdate - 180);
 
707924 rows selected.
 
Elapsed: 00:01:00.70
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=36425 Card=1 Bytes=40)
   1    0   SORT (UNIQUE NOSORT) (Cost=36425 Card=1 Bytes=40)
   2    1     MERGE JOIN (ANTI) (Cost=36423 Card=1 Bytes=40)
   3    2       SORT (JOIN) (Cost=18212 Card=2898455 Bytes=57969100)
   4    3         INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
   5    2       SORT (UNIQUE) (Cost=18212 Card=2898455 Bytes=57969100)
   6    5         INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
 
Statistics
----------------------------------------------------------
          0  recursive calls
        419  db block gets
      22565  consistent gets
      98692  physical reads
          0  redo size
   18461368  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          1  sorts (memory)
          1  sorts (disk)
     707924  rows processed


 

恩,consistent gets和建了索引时的minus方式一样,但是physical reads太大,返回时间太长---1min。同时用到了刚才建的索引。(呵呵,所以说,NOT EXISTS并不是什么情况下都比NOT IN更优啊)

在尝试用left join + is null代替not in:

 

6、

SQL> SELECT a.CDE, a.CID
  2  FROM
  3  (select DISTINCT CDE, CID
  4  from CCMMT
  5  where ADT < sysdate - 180) a,
  6  (select DISTINCT CDE, CID
  7  from CCMMT
  8  where ADT >= sysdate - 180) b
  9  WHERE a.CDE = b.CDE(+)
 10  AND a.CID = b.CID(+)
 11  AND b.CDE IS NULL;
 
707924 rows selected.
 
Elapsed: 00:00:25.46
 
Execution Plan
----------------------------------------------------------
   0      SELECT STATEMENT Optimizer=CHOOSE (Cost=54675 Card=2794940 Bytes=117387480)
   1    0   FILTER
   2    1     MERGE JOIN (OUTER)
   3    2       VIEW (Cost=18009 Card=2794940 Bytes=58693740)
   4    3         SORT (UNIQUE) (Cost=18009 Card=2794940 Bytes=55898800)
   5    4           INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
   6    2       SORT (JOIN) (Cost=36667 Card=2794940 Bytes=58693740)
   7    6         VIEW (Cost=18009 Card=2794940 Bytes=58693740)
   8    7           SORT (UNIQUE) (Cost=18009 Card=2794940 Bytes=55898800)
   9    8             INDEX (RANGE SCAN) OF 'CCMMT_IDX3' (NON-UNIQUE) (Cost=2 Card=2898455 Bytes=57969100)
 
Statistics
----------------------------------------------------------
         10  recursive calls
        118  db block gets
      22569  consistent gets
      31300  physical reads
          0  redo size
   18461368  bytes sent via SQL*Net to client
     519785  bytes received via SQL*Net from client
      47196  SQL*Net roundtrips to/from client
          6  sorts (memory)
          1  sorts (disk)
     707924  rows processed


 

效果不错,和有索引时使用minus在同一数量级上。

 

总结,以上几种方式中,效果最好的应该是第3种和第6种,buffer gets、磁盘IO和CPU消耗都比较少,返回时间大大减少,但是需要新建一个索引,消耗更多磁盘空间,并存在影响其它语句的正常查询计划的风险。而第2种方式应该是次好的。在返回时间上,和上面两种差不多,不需要新的索引,但是会消耗更多的内存、磁盘和CPU资源。

出于综合考虑,采用了第2种方式对生产库进行了优化。

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转载自blog.csdn.net/oracle_baidu/article/details/9133789