刚才用presentViewController去切换页面 出现了如下的错误报告
Warning: Attempt to present <UINavigationController: 0x6e8ade0> on <LoginViewController: 0x6b3ef90> whose view is not in the window hierarchy!
用万能的百度搜了下
如下是解决方法 亲测可以，记录一下
- (UIViewController*)topViewController
{
return [self topViewControllerWithRootViewController:[UIApplication sharedApplication].keyWindow.rootViewController];
}
- (UIViewController*)topViewControllerWithRootViewController:(UIViewController*)rootViewController
{
if ([rootViewController isKindOfClass:[UITabBarController class]]) {
UITabBarController *tabBarController = (UITabBarController *)rootViewController;
return [self topViewControllerWithRootViewController:tabBarController.selectedViewController];
} else if ([rootViewController isKindOfClass:[UINavigationController class]]) {
UINavigationController* navigationController = (UINavigationController*)rootViewController;
return [self topViewControllerWithRootViewController:navigationController.visibleViewController];
} else if (rootViewController.presentedViewController) {
UIViewController* presentedViewController = rootViewController.presentedViewController;
return [self topViewControllerWithRootViewController:presentedViewController];
} else {
return rootViewController;
}
}
、、这样进行跳转就可以了
[[self topViewController] presentViewController:nav animated:YES completion:nil];