const timeout = ms => new Promise((resolve, reject) => {
setTimeout(() => {
resolve();
}, ms);
});
const ajax1 = () => timeout(2000).then(() => {
console.log('1');
return 1;
});
const ajax2 = () => timeout(1000).then(() => {
console.log('2');
return 2;
});
const ajax3 = () => timeout(2000).then(() => {
console.log('3');
return 3;
});
const mergePromise = ajaxArray => {
// 在这里实现你的代码
};
mergePromise([ajax1, ajax2, ajax3]).then(data => {
console.log('done');
console.log(data); // data 为 [1, 2, 3]
});
// 分别输出
// 1
// 2
// 3
// done
// [1, 2, 3]
自己写的答案:
var data = [];
return Promise.resolve()
.then(ajaxArray[0]).then(res => data.push(res))
.then(ajaxArray[1]).then(res => data.push(res))
.then(ajaxArray[2]).then(res => {
data.push(res);
return data;
});