给定一个 Weather
表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。
+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+
例如,根据上述给定的 Weather
表格,返回如下 Id:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
解决一:
select b.Id from Weather a ,Weather b
where datediff(b.RecordDate,a.RecordDate)=1 and a.Temperature < b.Temperature
解决二:
select b.Id from Weather a ,Weather b
where date_sub(b.RecordDate,interval 1 day) = a.RecordDate and a.Temperature < b.Temperature
解决三:
SELECT w1.Id FROM Weather w1, Weather w2
WHERE w1.Temperature > w2.Temperature AND TO_DAYS(w1.RecordDate)=TO_DAYS(w2.RecordDate) + 1;