协方差公式推导

协方差公式推导

cov(X,Y)=ni=1(XiX¯)(YiY¯)n=E[(XE[X])(YE[Y])]

=E[XYE[X]YXE[Y]+E[X]E[Y]]

因为均值计算是线性的,即(a和b均为常数):
E[aX+bY]=aE[X]+bE[Y]

则我们有:
E[XYE[X]YXE[Y]+E[X]E[Y]]

=E[XY]E[X]E[Y]E[X]E[Y]+E[X]E[Y]

=E[XY]E[X]E[Y]

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转载自blog.csdn.net/u010770993/article/details/72676440