C++ const修饰this指针

#include<iostream>
using namespace std;

class test
{
public:

	//const修饰this指针 即指针所指向的内存空间
	//所以this->a,this->b一旦被修改就会报错
	void play(int a,int b)  const
	{
		a = 100;//编译没有错误,即const修饰的不是该函数的形参
		//this->a = 100;//编译产生错误
		//this->b = 200;//产生错误
	}
private:
	int a;
	int b;
};

int main()
{
	test t1;
	t1.play(1,2);
	system("pause");
}

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转载自blog.csdn.net/error0_dameng/article/details/82078646
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