UVA 12063 Zeros and ones 一道需要好好体会的好题



#include<bits/stdc++.h>
#include<stdio.h>
#include<iostream>
#include<cmath>
#include<math.h>
#include<queue>
#include<set>
#include<map>
#include<iomanip>
#include<algorithm>
#include<stack>
#define inf 0x3f3f3f3f
using namespace std;
typedef unsigned long long ll;
ll dp[35][35][105];
int n,k;

/*
ll dfs(int z,int o,int m) {
    if(z<0 || o<0) return 0;
    ll &ans=dp[z][o][m];
    if(ans>=0) return ans;
    ans=0;
    ans=dfs(z-1,o,m*inv[2])+dfs(o-1,z,((m+k-1)%k*inv[2])%k);
    return ans;
}*/

void solve() {
    for(int i=0;i<=33;i++) {
        for(int j=0;j<=33;j++) {
            for(int m=0;m<k;m++) {
                dp[i+1][j][(2*m)%k]+=dp[i][j][m];
                dp[i][j+1][(2*m+1)%k]+=dp[i][j][m];
                //cout<<dp[n/2][n/2-1][0]<<endl;
            }
        }
    }
}
ll  C[65][65];
ll solve2() {
    return C[n-1][n/2];
}

int id=1;
int main()
{
#ifndef ONLINE_JUDGE
   freopen("in.txt","r",stdin);
#endif // ONLIN
    int t;
    cin>>t;

    for(int i=0;i<=64;i++)C[i][0]=1;
    for(int i=1;i<=64;i++)
        for(int j=0;j<=i;j++)
        C[i][j]=C[i-1][j]+C[i-1][j-1];



    while(t--)
    {
        memset(dp,0,sizeof(dp));
        cin>>n>>k;
        if(k==1)dp[0][0][0]=1;
        else
        dp[0][0][1]=1;
        ll ans;
        if( (n&1) || k==0) ans=0;
        else solve(),ans=dp[n/2][n/2-1][0];
        cout<<"Case "<<id++<<": "<<ans<<endl;
    }
}










































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转载自blog.csdn.net/linruier2017/article/details/82142588