//题目:
Given an array nums and a value val, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
给定一个数组和一个值val,将所有与val值相等的元素去除,返回当前个数
class Solution {
public:
//if无论几行都要打大括号
int removeElement(vector<int>& nums, int val) {
for(int i = 0; i<nums.size(); i++){
if(nums[i] == val){
nums.erase(nums.begin()+i);
i--; //删除元素后改变下标 用i=nums.begin() i!=nums.end()就不用,很方便,但是不知道下标
}
}
return nums.size();
}
};